12.7V to approx. 7.5V

141

03:13:29

12.7V to approx. 7.5V
For JDLRHN

published 9 years ago

JDLRHN

9 years ago

good job thank you

Robert_Kidd

9 years ago

You're most welcome :-)

brian_boris

8 years ago

[BLOCKED]

schmobi2001

7 years ago

Thank you. I see that there is about 500 mA going through that transistor. I wonder what kind of transistor can handle that.

schmobi2001

7 years ago

Add to last comment ... i guess it needs to be a bipolar transistor 500v, 1A, 20W?

schmobi2001

7 years ago

Can you tell me why we need the diode and the zener? I found that it is possible to remove them and the ciecuit still works

Robert_Kidd

6 years ago

The Zener provides a stable reference voltage. In this case the diode is added to give the extra 0.7V that was needed to get 7.5V since Zener diodes only come in certain voltage valves.

Robert_Kidd

6 years ago

If you remove the diodes the circuit will not regulate the output voltage - try adjusting the input voltage whilst monitoring the output voltage.

Robert_Kidd

6 years ago

With a maximum current of 0.5A and a voltage drop across the transistor collector emitter of 12.7 - 7.5 = 5.2V the very minimum dissipation would be 0.5 x 5.2 = 2.6W. I’d suggest a transistor with a power rating of at least 5W. I don’t have access to data sheets at the moment but I will come back with a suggestion or two..

kiani

6 years ago

[BLOCKED]

hoppigksne

5 years ago

Jdrlrhn?

hoppigksne

5 years ago

Resistor shorted!

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