What is the amperage

One in each case http://everycircuit.com/circuit/6208690872385536

@2ctiby, The form factor part is not fully correct. The factor 1.11 is only valid for rectified sin wave curves. Avg voltage of a rectified 1V peak sinwave is 0.637V multiplied with 1.11 is 0.707V. You can calculated a formfactor for any other periodic wave form but it will be different to 1.11. Cheap DMMs do use form factor of 1.11 for sin wave but not for any other possible wave forms a separate factor.

It applies to any sine wave,  not just a rectified sinewave, but yes it was too much of a generalisation there by me. eg a triangular wave is nearer 1.15 and a pulse is nearer  √ ((mark + space) / mark)    I stand corrected thanks....it is there just a quick way to convert the rms to avge.

A not rectified sinwave average is zero.

Yes... The 'average' is zero so the avge needs to be applied to just the positive half wave, but the 'rms' can be applied to a non-rectified full sine wave because squaring the values removes the negative signs. I was referring to the difference between starting the rms procedure etc with a full sine wave cp starting with an already fully rectified sine wave ...just a little mis-understanding there....both will have a form factor of  π/(2√2) and a similar rms

And because its Zero you can not compare it with a true rms calculation as you notice now and here. And only the positive half won't help either. The form factor won't be 1.11. Check this http://everycircuit.com/circuit/5671887606120448

Your link does not work but you are mis-understanding what I am saying...let me phrase it differently: You said 'The factor 1.11 is only valid for rectified sine wave curves. Avg voltage of a rectified 1V peak sinwave is 0.637V multiplied with 1.11 is 0.707V.' I read that as you implying that a non-rectified sine wave cannot be used to be operated on by a rms. I was replying by stating that a non-rectified sine wave can indeed be used to obtain a rms (which can then be used with the avge pre-rectified sine wave...0.637 to obtain the 1.11). The act of performing the rms operation mathematically converts the non-rectified wave in to a rectified wave inasmuch that all the negatives become positive....My point was that the initial wave here is non-rectified, ready to be operated on by the rms calculation.

http://everycircuit.com/circuit/5671887606120448

Your circuit emphasises a different interesting point that a cheap DMM only approximates an rms either by taking an ordinary + average or a peak and then applies the necessary alteration to read out an rms estimation cp an expensive device which takes many samples to obtain a 'true' rms...all interesting stuff.... perhaps time for us to get back to the original theme of the original question and agree on the answer of one amp and one Watt rms as described.

≈997mA and ≈994mW ;-)

Haha...do we need a long further discussion about rounding errors or is there a key missing point suggested here? ...maybe we should just leave it as thought provoking!....if only we knew what π/(2√2) meant?!

Lol hurz

It wasn't for you 2ctiby

How easily a cheap DMM can give a different outcome...now V = 1.01 so I = 1.01A and P= 1.02W cp 997mA and 994mW ... We always need to be aware of spurious accuracy and the need for sensible appropriate rounding in line with our starting criteria (V of 1.41 originally and no decimal places after the 1 Ohm) http://everycircuit.com/circuit/5277713325096960 We should usually take the lowest of the criteria and do our final rounding to that....eg no decimal places for Ohms so appropriate final rounding reqd. Better still...we may often need to present results with an error estimate such as standard deviation and confidence interval.

@2ctiby, you messed up my circuit and changed the form factor from 1.11 to 1.12! Be careful with quick shots and try to be more accurate. Thanx