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andrewvinicius
modified 4 years ago

Conversor de corrente 4-20 mA em tensão 0-5 V

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01:46:16
Para valores de 0 - 3,3 V => R2=3,91 kohm Para valores de 0 - 5,0 V => R2=10,8 kohm Para valores de 0 - 10,0 V => R2=31,7 kohm Para mudar o range de corrente, é preciso fazer o ajuste segundo a equação: Vout = I.R3.[1+(R2/R1)] - Voff.(R2/R1) Com R4 = 150 ohm, e R1 = 10 kohm Para range de 4-20 mA, tem-se 4/20 = 20%. Assim, sobra 80% de ajuste, que deve ser usado para dividir pelo limite máximo de tensão, ou seja, se for 4-20 mA e range de 0 a 10 V, então divide 10V por 80%, que resulta em 12,5 V. Portanto, será: 12,5 = 20m.150.[1+(R2/10k)] - 0.(R2/10k) => 12,5 = 3.[1+(R2/10k)] => 12,5 = 3 + 3R2/10k => 12,5 - 3 = 3R2/10k => 9,5 = 3R2/10k => 9,5.10k = 3R2 => 95k = 3R2 => R2 = 95k/3 => R2 = 31,7 kohm
published 4 years ago
Redstone_guy
4 years ago
I assume we adjust the potentiometer?

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