Another Class-G Amp

That's a class G man. Class H amps continuously modulate the power supply rails, Class G amps modulate the rails, only for a portion of the wave, sometimes at several different levels, but basically have only a few switching points. I think I have a basic class H amp posted somewhere here, I'll try to find it.

http://everycircuit.com/circuit/5339186913869824 here's an example mate

I tried googling the link you gave me (because on apple devices I can't follow them properly), which always worked in the past, but then it said that the site could not be reached and that it's DNS address could not be found. I tried reloading, but that didn't work.

Is a class-H amp one that measures the peak amplitude of the wave, and sets the power level to just above that for the entire wave?

Or is it something else? I tried googling the difference between class-H and class-G with no luck, so maybe you can help me understand?

Lets see if jason9 will find out whats wrong with Mr foul mouth buggys simple example is wrong, so I do not need to do that http://everycircuit.com/circuit/5339186913869824

I found your "Class H amp simple example" circuit online, but, unfortunately, I could not open it in the app or in the browser. But I could see the description and a picture of the circuit, leading me to think that class-H amps modulate their power rails around their output, while class-Gs probably modulate their power rails around the input. Is this correct? @hurz, I'm sorry, but I can't find out what's wrong with @thebugger's circuit, because I can't open it from the internet, and it doesn't show up when I search it's name. Also, could you please not throw around insults like "foul mouth"?

But he is a foul mouth.

Even if he is one, that doesn't mean you should call him that, especially because, I don't mean to insult you, but, I think you probably have a fouler mouth, or brain, or... something. Whatever it is, I just mean to say that @thebugger comes across as nicer than you. Really though, I don't mean to insult you. I'm just stating what my opinions are.

And he is still a foul mouth.

In what way?

Best example threads he deleted (but there are still some good ones availavle). The very first one we had on a third party noob user he ATTTACKT together with Mr pip, he deleted all his foul mouth stupid comments. 20 bullshit comments or more... just a foul mouth with 50years expirience after he is active in electronic for about 5!

It would be easier for me to understand if you could somehow show me some of this.

You know what you asked for?

Yeah, I know that my request is probably impossible, but I'm just saying that that's what it would take to convince me.

I see potential in you and your intelligentes, check this and forget after you understand. http://everycircuit.com/circuit/6333702607208448 "Single Rail To Split Rail"

In terms of how much he's a foul mouth, I think that he was only being like that because you were getting on his nerves.

Disregarding the weiner fart hurzy's snobby comments, I'll poat the circuit publicly to see if you can load it.

Search for Class H Amp simple example

Buenos dias, buggzy you little asshole!

Should I be impressed you know a word or two in Spanish? I know some as well. Vete a tomar por culo hurzy, a tomar por culo!

I don't really understand how you class-H amp works, @thebugger. I get that the output modifies the supply rail, but I don't know what effect it actually has. Does it increase/decrease the current of constant current source that feeds the class-A part of the amp? If so, how does it change the current of the constant current source? Wouldn't the design of the constant current source prevent the supply rail from affecting the current? Or does it change the supply rail to reduce the amount of energy dissipated in the constant current source? If so, wouldn't the device that regulates the supply rail dissipate that energy instead? The only way I can imagine that the supply rail modifier device doesn't dissipate the energy it's trying to save, is if it's some kind of buck converter, but those respond far to slow. So, how does it improve efficiency? The only way I can see it improving efficiency, is if it measures the peak amplitude of the desired output wave, and sets the output of a buck converter to that level, basically making it so that the efficiency is always at the max of 50% no matter the amplitude. But, this, of course, isn't how your amp works, as it doesn't include any buck converters. So, how does it improve the efficiency???

👍

Without the use of buck converters, the only way I see to increase the efficiency is to use different supply rails that you switch back and forth from. Because, without buck converters, however much current that goes out of the amp, is equal to the current coming from the supplies. And a lower voltage supply can't send current to a higher voltage rail, so, the only way to send current to the higher voltage rail is with a higher voltage voltage source. This means that you have to switch between voltage sources instantly, which I believe makes it a class-G amp. And, speaking of class-G amps, I should probably rename my class-H circuits so that it says class-G, like it should.

Imagine it this way. The supply rail, you've chosen is 10V at 2A for instance. When swinging a higher voltage supply on top of that in respect to the output you basically keep the VCeo of the transistors constant (e.g. their voltage drop doesn't increase). No increase in voltage drop means you don't have an increase in dissipation. So the primary amp for instance drains 20W in idle, and will also drain 20W at full power. The extra power needed to maintain the load carrying capability, will come from a more efficient amp, like a class B amp or even a class D amp (although I haven't seen a class D amp interpretation). Basically you get to use all the class A amp perks like linearity, but with increased efficiency.

I've placed a voltmeter on the circuit for you to see, how the voltage drop across the constant current source is held steady, where as you know a normal constant current source will vary the voltage to keep the current steady. So when both V and I are held constant, the excess power dissipation ia shifted to the more efficient amp, like the class B amp driving the circuit.

When "V" is constant across your "woodoo black magic current source", then its call Resistor! Resistor constant, voltage constant, current constant.

Yes, therefore dissipation constant. The power handling gets shifted to the more efficient amp, while maintaining the good linearity of the class A amp. I've always found class H amps quite ingenious, it's like a cheap parlour trick, but highly effective one.

you better shut up and replace it with a resistor.