Output Voltage Bias Remover

whats the advatange of an RC highpass?

What do you mean? The capacitor is part of the integrator op-amp which gets it’s input from the output of the amplifier op-amp.

Think about a solution without any OpAmp. Right OpAmp are cool, but not always needed if they do not bring an advadtage, right?

you need GREEN here is green http://everycircuit.com/circuit/5071829537652736

Another last (trust me) redirect to one of your circuits :- http://everycircuit.com/circuit/5343506301452288 It's pretty weird to ask you certain things about the old circuits that you'd made but I find your circuits challenging and really interesting. That's why. I'll delete all the comments of mine that I had put in your circuits. Once again, I'm really sorry for littering your posts. If you're getting an awkward sensation, inform me and I'll stop this "hocus-pocus".

Don’t worry, I don’t mind random unrelated comments on my circuits.

If anything, what makes me feel awkward is your saying how you feel awkward.

The integrator (right OP-amp) charges or discharges its capacitor according to the voltage across its two inputs (the green wire and ground). When the voltage on the green wire is positive, it charges the capacitor until the average voltage of the green wire is 0. When the capacitor charges, it raises the reference voltage of the amplifying OP-amp causing the output voltage to drop since it’s an inverting configuration. So, when the average voltage is 1V, the integrator starts charging the capacitor causing the output voltage to drop until the output voltage averages to 0 at which point the integrator stops doing anything. When the average voltage of the inout drops back to 0, the average voltage of the output drops to -1V causing the whole process to proceed once more, but in the opposite direction, once again returning it to 0V.

A simpler implementation of this circuit that should behave exactly the same is a high-pass filter with a buffer OP-amp at the output. After all, that’s all this circuit does. This simply filters out the low frequency portions (DC) in an unnecessarily complex way. I suppose I didn’t realize the simpler solution when constructing this.

Thank you @jason9. However, I feel that the real question was left unanswered (notice the comments getting fewer in your recent thread):- http://everycircuit.com/circuit/5850588150235136