zorgrian

modified 5 years ago

💡Sinusoidal⏧Wave⏧Generator💡

152

02:08:48

⌁⌁⌁This is not practical, as the insertion loss is over 50bB⌁⌁⌁

⏧As the Irish say, "If you want to get to Tipperary, well I wouldn't start from here."⏧

For those of you who are LED challenged, or who suffer from other afflictions such as pretensions of adequacy, the above means, this ain't the way to make a sine wave. However, if you find yourself stranded upon a desert island with only resistors, capacitors and square waves, at a pinch you might use this method.

Also Note: it is imperative to recognise this circuit as an unapproved modality. Thee methode used here is not not not good

published 5 years ago

kiani

5 years ago

Could you show us the 50 (bB) (dB), (db) {whatever} insertion loss plz.

GLaDOS

5 years ago

Still being a fequency filter. Change the frequency of the square wave slowly from 0 to max and observe what it does

zorgrian

5 years ago

@glastnos, It being a frequency filter yes. Ok so it being very very much frequency falterings, put put ding ding

zorgrian

5 years ago

@kiani, OK nice commentings... So if you replacing the upgradings of the square wavings to a sign wavings, you vwill be seeings thee approx -21.4dB insertion lossings... But Notings, that this is unfair representation

zorgrian

5 years ago

@kiani... are you going to war with meings? Vwatt have I donings?

kiani

5 years ago

@ Zorgrian yes thank you for reply.... And no I don't have war with anyone. Peace upon earth and all earthlings.. Ants, dogs, cats,.. But the animals on EC have something that animals in jongle don't have and that is HATE.,, no amount of love i offered bought one onze if love on this commercual shit called community. Only one, twi, or three people, inclusive.

prinzrainer

5 years ago

if you have capacitor in the island im sure you can also find an inductor or least wound it yourself http://everycircuit.com/circuit/4712087394451456 this has a gain of 20dbm with 180° phase

kiani

5 years ago

Yes you could cut off the legs of too many capacitors and wind an inductor, and use the leg less caps as fire crackers haha.

zorgrian

5 years ago

@kiani, I thank thee for thy suggestion and will (obviously) immediately set upon said capacitors to chop off their legs. Some will ask, "why not their heads?" * * And to this I shall say simply, "I didn't like Tony Bliar while he was in power, I like him even less as a Catholic War criminal"

zorgrian

5 years ago

@heinZrainer, I see, the idea, but unfortunatly on the island there are the nasty horrific zealous UmBongoLED tribe, who do not like windings. When they see a winding or detect any perturbation of the Magnetic Flux Layer, they decapitate everyone, including themselves!

zorgrian

5 years ago

The tribe, do not actually know when or why they must kill all L values, and all attempts to rectify them of mental problems have failed. After many years, we now assume that all *LED tribal peoples are hopelessly lost and hostile. It is for this reason that we bomb them and has nothing at all to do with any Oil, Diamonds, Gold, Gas or other minerals that they have huge natural resources of

hurz

5 years ago

@prinzrainer, 20dBm is an absolut value and not a relative gain. Do you mean 20dB gain? Or you mean now its 10dBm and after modification its 20dBm, that would make sense. But 20dBm gain doesn't make a lot of sense

zorgrian

5 years ago

@REINSTOMPER, I agree with @Hurz, who points out that dBm is an absolute value; as such it does not represent any gain or loss

zorgrian

5 years ago

@prinzShuffler, I do like your http://everycircuit.com/circuit/5105465563021312

prinzrainer

5 years ago

@hurz, sorry it was 20mdB relative to the source.

hurz

5 years ago

thats one more thing 20mdB is 0.02dB and thats nothing relative to anything

prinzrainer

5 years ago

i was talking about the ratio between the input and output voltage, G=20log(Vout/Vin), using ac analysis here in ec it concluded that the gain of the circuit is ~2mdB at 1KHz. So given a 1V 1KHz input voltage the output voltage should have: 0.02=20log(Vout/1), 0.02/20 = log(Vout), Vout=10^(0.02/20), Vout=~1.0023

hurz

5 years ago

or 0.23% which is almost nothing, right?

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