5v dc capacitor step-down 1.24v

293

05:19:51

so I'm wondering if this would be a workable way to supply something that uses a AAA battery from a 5v 1000mah power bank from Walmart for 5$  I'm willing to test for curiosity but if ill advised  I will not

published 8 years ago

592azy2circuitdude

8 years ago

I'm no expert, but I think not. You would be powering something (a load). If you replace the volt meter with a load (a resistor for example) no current flows. But your circuit is pretty interesting!

crake

8 years ago

The problem is that those capacitors will not pass DC current. The 5V source you're using is a DC voltage source. Have you considered another way of doing this?

zorgrian

8 years ago

It is vastly unfortunate, that the might of this engineering, at least in this quadrant of the multiversity of dimensional spacetime, does not perform the requested function.

zorgrian

8 years ago

So, you need to look for a mechanism that reduces voltage from 5 volts to 1.5 volts. The simplest way of doing this is a resistive divider. This will work but it is only really useful when you need only low current. Check out all the examples in EveryCircuit.

eekee

8 years ago

This is just EveryCircuit trying to be clever. At the start of simulation, it precharges the capacitors based on some assumptions. In some circuits it saves a lot of time. In others, like this one, it's misleading.

hurz

8 years ago

@eekee, I dont know what is misleading here. Set the voltage source to zero and restart the simulation. Tune up the voltage source to 5V and voila you get 1.24V this will also work on your breadboard if the caps are not to different in leakage.

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