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jg1xmv
modified 7 years ago

Make Electronics-Ex 11a

2
4
116
03:14:42
Use simulation speed of 1s/s and change one of the Resistor values from 470k to 500k to start the oscillation (otherwise it will take 30s+), then you can switch it back to 470k. I have tried to give myself a step by step explanation here: https://www.tapatalk.com/groups/japanpeuf/oscillator-circuit-using-transistors-and-capacitor-t1313175.html
published 7 years ago
BillyT
7 years ago
A couple of diodes help square up the oscillations a bit, they do require that slightly smaller biasing resistors be used. http://everycircuit.com/circuit/6213568111050752
jg1xmv
7 years ago
Thanks. Yes, I saw how people use diodes to make the oscillation more square but to be honest this is a bit ahead of my very basic learning curve. The one thing I was wondering about is when current flows through the left hand-side 4.7K resistor and through the transistor directly below that, why there is no current flowing through the 100k resistor and to the base of the left-most transistor thereby allowing current to flow through to the LED. I know that if it was the case then the LED would be ON all the time but I am not sure I understand why the current could not theoretically flow through there as well.
BillyT
7 years ago
I've removed the diodes, and high lighted the base voltage, you really need to understand how the circuit biasing works. http://everycircuit.com/circuit/6213568111050752
jg1xmv
7 years ago
Ok I found my answer. Current does flow through the left-most transistor when the LED is OFF. It is just that it is not enough even with the amplification of the transistor to turn the LED ON. If I lower the value of the left-most 4.7K ohms resistor and get more current to flow through that transistor, then the LED stays on all the time (with a flicker in between).

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