modified 5 years ago

Please help - EXPLAIN -

00:32:08

lets say if i take 20mA 2V LED.  If i apply ohms law here i will get 100ohm resistance in the LED. If i drow two circuits that using LED and other one with resistors (100ohm) the voltage and current overall of the circuit should be similar between the two circuits. Because
 2V / 20mA = 100ohm (LED resistance)
Why is that voltage and current of the point are different between these circuits.

published 5 years ago

suklaji

5 years ago

That the different between resistor and diode . LED self drop.

wyoelk

5 years ago

There is also capacitance and the diode effect to consider

gabidegabidegab

5 years ago

Le comportement du courrant de la LED en fonction de la tension a ses bornes est une exponentielle et non une droite. On ne peut donc pas la comparer a une resistance. 2V/20mA n'est que l'expression d'un point de fonctionnement pour laquelle la LED va briller correctement. https://images.app.goo.gl/HyAFZA3JkQ9EqV8g7

maxmax_66

5 years ago

Diodes, including LEDs are non linear components. Ohm’s law is a linear description relating the proportionality between current and voltage in a conductor. As a semi conductor, an LED is a non ohmic device and exhibits a non linear relationship between the current and voltage. You cannot apply Ohm’s law to LEDs as you would a resistor.

Ravidu

5 years ago

Thanks all 🙏 i really appreciate it.

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