A Simple RL circuit with Calculations

278

04:22:54

Whereas: 
Freq. 5Khz @ 10 Vdc
a. Calculate the Current in the series RL circuit
b. Calculate the Phase Angle 
c. Calculate the admittance

Solution:
Xl= 2 π fl
XL= 2 π* 5Khz * 5.1milli Henry
XL= 51π = 160.22 
Whereas Z= impedance
Z=( R^2 + XL^2)^ 0.5
Z= 366.83 ohms
Therefore Current in Series RL Circuit
I= Vdc/Z
I= 10V/ 366.83 ohms
a. I= 27.25mA * minimum Current as seen on the sinusoidal waveform by approximation

b. Theta= Inverse Tangent (XL/R)
Theta= Tan-1(160.22/330)
= 25.89°

c. Z=1/Y
366.83 ohms=1/Y 
Y= 2.72 milli Siemens

published 4 years ago

add comment in editor

EveryCircuit is an easy to use, highly interactive circuit simulator and schematic capture tool. Real-time circuit simulation, interactivity, and dynamic visualization make it a must have application for professionals and academia. EveryCircuit user community has collaboratively created the largest searchable library of circuit designs. EveryCircuit app runs online in popular browsers and on mobile phones and tablets, enabling you to capture design ideas and learn electronics on the go.