This is a comparison of what the signal attenuation of a moon bounce looks like. Since the moon is a very poor reflector and the path loss between the earth and moon and back again is huge, an attenuation rate of -252dB@144MHz is expectant. This is what such an attenuation looks like. You'd probably have more power induced in your body from standing across the room from a small transformer or something. Anyway NASA has successfully bounced and received a signal from the moon at this attenuation ratio with a transmission power of only 3mW. Hah, I've been studying telecommunications for years and it never ceases to amaze me how far we've come since the damn of the radio a mere 100-150 years ago. Anyway not sure if the comparison is correct, because the source didn't say if the attenuation was in the power level or voltage level, and what was the reference level to begin with. I took a reference level of 7V/50ohm in this example.