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moh
modified 11 years ago

It doesnt work..... WHY

2
11
168
03:50:05
published 11 years ago
vk40471
11 years ago
connectng resistance to series with current source it worked
MayukhSobo
11 years ago
Don't act like a fool. You have shorted the voltage source. How can it will work?
bryanthehacker
11 years ago
Inductor resistence is 0 ohm = short circuit. Insert a series resistor
banz234zza
11 years ago
good
faceblast
11 years ago
EC coils are all 0ohm DC resistance. put a resistor in series to simulate a real inductor
joelarol3
11 years ago
Or put a diode in series with the inductor so it can be fed in one direction only. Inductor become close switch in AC.
mprrjames
11 years ago
This circuit should work.. There is a problem with the simulator, inductive reactance has an impedance, if the source is AC, then the inductor isn't a dead short, it will have a resistance value depending on the frequency of the source, the inductor also changes the phase of current vs voltage. For a split second in the simulator, the rise from 0v to the peak, say 30v is dc.. The simulator probably freaks out just at tbe beginning of the waveform
zooape
11 years ago
Add a cap between upper rail and AC then it will work
moh
11 years ago
Thank u all for ur comment's ...I understand from u that the inductor becomes a shourt circuit with AC signals that's something new for me, could you explain to me more about that ? :-)
olly25
11 years ago
Hey... just to help, the inductor will always have some sort of resistor in series with it (inductors are coils of wire -how well they conduct determines the Q, and the program doesn't take that into consideration)... so to alleviate this problem, just put a resistor of .001-3 ohms in series with your inductor's branch.
robw
5 years ago
How funny....I tried to build this same circuit to understand a concept while studying for a ham radio license. And I had the same problem. Adding the small resistor right next to the source fixed my issue.

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