EveryCircuit - My 6400 Farad capacitor bank

7 years ago

one idea, split them in 2 x 8 x 400 and connect them in series you can make a portable USB power bank.

7 years ago

@hurz Thanks for the idea! I used a capacitor calculator and the outcomes of your suggested setup can hold nearly twice the energy! Thanks!

sshsslfun

7 years ago

Wait, the joule rating is twice as high than the previous set up but te wattage is at a 4th of the original wattage, why is this?????

hurz

7 years ago

standard power bank chips with 5V booster do have 3 to 4.2V battery limit (lithium ion), dont forget

hurz

7 years ago

the organisation of caps (how many parallel or series) does not change the energy you can store. The energy is always equal in any topology. however the voltage does change and makes it more applicable for different tasks.

jason9

7 years ago

Ok, I’m imagining two hypothetical 1V 1F capacitors in series vs in parallel. If they are in parallel they have 2F at 1V. Since it’s 2F, it’s two coulombs per volt, with a max voltage of one volt for a max storage of two coulombs. If they’re in series it makes a 1F 2V capacitor bank. Since it’s 1F it has only one coulomb per volt, but it has a max voltage of 2V for a total of two coulombs. So, no matter the arrangement, two capacitors with a one coulomb capacity will make a capacitor bank of two coulombs. However, since coulombs are a measure of current over time (one amp for a duration of one second), it says nothing about joules (power over time, one watt for a duration of one second) without a measure of voltage. Since the series configuration can store twice as much voltage as the parallel configuration, the series configuration does in fact store twice as many joules. So, @hurz, by “the organization of caps does not change the energy you can store” you must mean coulombs, right? Because if you mean joules then I need an explanation on how the parallel configuration can store as many joules as the series configuration. @sshsslfun, what do you mean by quarter the wattage? Both setups should give same wattage when fully charged, but the series one should have four times the discharge time because it can handle half the current but twice the voltage.

hurz

7 years ago

in series of 1F you get only 0.5F in total. This is compared to the parallel configuration 2F the factor 4 here we have the quardatic dependency. The energy in any topology is equal.

hurz

7 years ago

check your example http://everycircuit.com/circuit/6169121573306368

2ctiby

7 years ago

@hurz ... No ... The total voltage in each of your schematic circuits should be 1v as per each battery ... not the 2v which you have used in your Serial calculations. The total energy in the parallel circuit capacitors should be 1J and there should be four times more total energy stored in those parallel circuit capacitors (ie 1J total) compared with the energy stored in your series circuit capacitors which should be 0.25J total ... The parallel and series energy totals would not be equal in those component similar-value setups.... Where did your 2v come from?

ViolationMad

7 years ago

@2ctiby, @hurz just follows through @jason9's mind experiment. "I'm imagining two hypothetical 1V 1F capacitors in series vs in parallel". I don't see any problems with that an as far as I know he calculated everything perfectly fine.

2ctiby

7 years ago

@ViolationMad ... The calculation is wrong, and if jason9 had said that 57v or 243v etc is correct in that mentioned 2v place then would hurz have carried on using that as though it was appropriate.

hurz

7 years ago

The original idea is to build a power bank which is in voltage between 3V and 4.2V for lithium ion (chips are plenty available). I dont care any tricks or misstakes or blabla you make by calculating anything, its your problem. A single capacitor can only work with upto 2.7V before it gets damaged. so we put two of them in series and we can go upto 5.4V if nicely balanced! This is what i recommend as a quick idea to make practical reuse of @sshsslfun 16 capacitors. lol

2ctiby

7 years ago

@hurz ... your link circuits calculations wrongly describe a false energy result for your shown circuits there... Feel free to correct the result for what you have shown there.... and re-think your insinuation that both the parallel and series circuits there must always produce the same total energy result.

hurz

7 years ago

i dont see anything wrong. two batteries in parallel do have still equal energy as the same two batteries in series.

hurz

7 years ago

@jason9, i think the only mistake you have done is the assumption two 1F caps in series are still 1F but they are just 0.5F in total. Check my calculation i took your example values.

2ctiby

7 years ago

@hurz ... I see that you have altered your link circuits now. Before this, both of your batteries were 1v each with two 1F caps each circuit (series and parallel). The total series voltage then should have been 1v across the two series caps. Your series calculations however said 2v for that, and so produced a wrong result for the total energy there. Never mind, we all make mistakes as you did there. Now you need to alter the calculations there to suit your newly shown circuit component alterations. The calculations there still show the previous wrong workings for the earlier two series caps of 1F each with a 1v battery at this time of writing.

hurz

7 years ago

the calculation is untouched and still correct, i dont know why you have problems understanding the 2V. But as i already said, its your problem.

2ctiby

7 years ago

@hurz ... the stored energy in the caps is what we are dealing with... not the energy of two similar batteries. The charge of each cap in series is the same for all of the caps there in series, regardless of their capacitance values. The total series charge is also equal to each of the single similar charges too. The voltage across each alters to ensure that. With two similar caps, the voltage between is then simply half of the supply voltage.... look at your series circuit or any. The total sum of series voltages results in the battery voltage. ... hence you should have used 1v in your original link as the series total V, not 2v ... The charge is 0.5 , and the total series capacitance is 0.5 as you described (Q=CV ...Q= 0.5 × 1), so then with the energy being (1/2)QV or (1/2)CV^2 ... the total series energy should have been: 0.25J (the total parallel energy works out at 1J ... which is four times more than the series total energy 'stored in the caps' which is what we are after).... hope that helps.

hurz

7 years ago

1+1=2 dont know why you try so hard to get 1V. The voltage is double in the series topology. You seems to be having problems to accept the simplest facts. You have to life with 2V, sorry my little troll.

maxmax_66

7 years ago

The energy of a 2 cap parallel topology charged to V : E = (1/2) (2C) V^2 = CV^2. The energy of a 2 cap series topology charged to 2V : E = (1/2)(C/2)4V^2 = CV^2. The total energy is the same for each topology.

hurz

7 years ago

thanx @maxmax_66 to clarify this. Funny to see how many joules some investe to look like a complete idiot.

jason9

7 years ago

@hurz, yes it would seem I made a silly error. Two 1F caps in series is indeed 0.5F so same storage no matter what.

jason9

7 years ago

But with series you get twice the voltage at half the current capacity.

sshsslfun

7 years ago

Question: What is a Culomb and what is a joule??

2ctiby

7 years ago

@maxmax_66 ... In the hurz link series schematic there was a 1v battery. That schematic depicts just 1v across the two series caps of 1F each .... Where do you get your 2v charge in that series schematic ?

2ctiby

7 years ago

The voltage across each cap is 0.5 volts as can be seen there between the caps, (ie half of the battery voltage), and Q=CV ... so Q=1×0.5 ... ie: the charge on that cap is 0.5 Coulombs ... and likewise for the other cap. The charge is in Coulombs, not volts, and the volts are as seen across the caps there correctly as 0.5v. There is no 2v in that situation.... there is no constant current supply to increase the voltage there beyond the 1v battery supply.

2ctiby

7 years ago

Readers should notice who has started the "troll/idiot " insults in this thread rather than sticking to amicable electronics discussion.

hurz

7 years ago

@jason9, yes the voltage can be doubled, so what you gain by voltage, for the energy, you lose with the topology series and less capacity. But the total amount of energy for a parallel or series topology is identical. 1Joule in your example. @sshsslfun, any plan what you make with your 16 caps? I still have some 3000F 2.7V and never finished the project 😉 my investigations stops at some clever balancer concepts. Actually one concept i have tested and its working fine.

sshsslfun

7 years ago

@hurz Not sure, thinking about it, I could turn the capacitor bank into an auxilary power unit for starting and warning up my old impala, but I wont be doing any mods to my impala for a year or two so that idea is left in queue. Another idea would be to make a railgun, but for the last two ideas Id need to know more about engineering and electronics before I can make even their driver circuits. Its just going to be in my closet for a year or two.

2ctiby

7 years ago

@jason9 ... you now know that the total capacitance for the series circuit of 1v across two 1F capacitors is 0.5F ... The total series battery V is 1volt ... so by using Q=CV to obtain the total charge, we get Q=0.5 × 1 ... ie: Q=0.5 Coulombs total charge. The total charge in a series circuit is the same as the individual charge on each of the series capacitors (regardless of each capacitance value). So, we can now use that Q to find V stored across each capacitor by re-arranging that formula to read as: V=Q/C ... so V=0.5/1 ie: V=0.5 volts for that capacitor of 1F ... the other capacitor is exactly the same, and so the volts across it is also 0.5v ... The total voltage is the sum of all of these series voltages, and they all add up to 1v here (because there are only two caps at 0.5v each as found). ... The main thing then, is to realise that the voltages sum to form the battery total voltage. ... we could describe that as saying that the cap voltage is doubled in this case, but we have to understand that reason why ... which I have just explained, and we must realise that it is a doubling of the 0.5v ... not a doubling of 1v here. You did not appear to understand that ... and neither did Hurz since he used a total V of 2v which does not apply to this circuit ... and which gave wrong energy results, which he still does not understand.

jason9

7 years ago

@2ctiby, your last comment (and probably prior ones too, I didn’t read them all) was too dense for me to understand. Could you please state clearly and concisely what @hurz and I appear not to understand?

jason9

7 years ago

@sshsslfun, a coulomb is the number of electrons equivalent to one amp for one second. A 1F capacitor with 1V across it has a charge of one coulomb. Coulombs of charge can be calculated as C=FV where C is coulombs, F is farads, and V is volts. A joule (pronounced the same as but not to be confused with a jewel) is a measure of energy. A watt is a measure of energy flow. A joule is the energy equivalent to 1W for one second. A 100W bulb uses 100J every second. If a buck/boost converter steps up/down the voltage of a capacitor bank with 1000J in it, then it can’t charge another higher/lower voltage capacitor bank to more joules. Conservation of energy. However, since coulombs is a measure of electrons with nothing mentioned about voltage then ten coulombs of current at 1V is the same as one coulomb of current at 10V is the same as 10J. So, while joules are conserved (or even lost, but that’s just a transformation to heat or motion of a speaker/motor), coulombs are not conserved. Think 10:1 transformer, one amp at the input, ten amps at the output, but one tenth the voltage at the output. Joules are conserved, but not coulombs.

2ctiby

7 years ago

@jason9 ... One step at a time then: Let's stick to your series suggestion of 1v battery across two 1F caps in series. ... Q=CV where Q is total charge in coulombs, C is total capacitance in Farads, V is the total volts of the circuit. Then Q= 0.5 x 1 ... so the total charge is 0.5 Coulombs. Do you agree with that?

jason9

7 years ago

Yes.

2ctiby

7 years ago

@jason9 ... The total charge in a series circuit is exactly the same value as the charge in each and every series capacitor there ... so that charge value of 0.5 coulombs can now be used for each individual cap ... Q=CV again, but now use 0.5 as Q, and use 1F as C ... so we now have the voltage across one of the 1F caps: V=Q/C ... V=0.5/1 ... so the V across that cap is 0.5volts. Now do that same procedure with the other identical cap, and that too has 0.5v across it. Are you ok with this finding of 0.5v across each of the two caps?

jason9

7 years ago

Yes.

2ctiby

7 years ago

@jason9 ... The total voltage in a series cap circuit is equal to the sum of the individual cap voltages. ... Here we have 0.5v + 0.5v = 1v total voltage. That total voltage, not surprisingly, is the same as the supply battery voltage: 1v ... Here then in this circuit we see that although a cap voltage could be described as 'doubled', we now realise that it was in fact halved fom the battery 1v ... the 'doubling' refers to 2 x 0.5 to give us the total circuit volts ... which is the battery supply value. ... That 1v is the one and only volts value that we should be using for finding our described series circuit total energy (not 2v). We could then compare series and parallel circuits using the correct appropriate values... Do you agree?

jason9

7 years ago

Your saying we measure both series and parallel with the same voltage (1V)?

hurz

7 years ago

sounds like a brain whasing methode @2cent using here as argument. 1V for both cases. 1Volt! right 1V. One volt. Just 1.0V, funny funny

hurz

7 years ago

what about 5.4V

2ctiby

7 years ago

@jason9 ... Let's finish the present series assessment first ... that 1v of the battery here is also the total v of the series added caps as you have found ... so that is our required total voltage for the series circuit. There is no other v which we are involved with in this described series circuit. 1v end of story for that. If you are ok with that, we can continue to find the total energy stored in that described series circuit. ... if not, then we need to know why you cannot accept that 1v total ... so how are you fixed about that total series 1v ?

hurz

7 years ago

No, its 2V, or if you are following us on this electronic topic from @sshsslfun its 2 x 2.7V = 5.4V. 1V was choosen by @jason9 for a simple experiment and would cause for a series topology 2V. Fuckin 2V and not 0.5V+0.5V=1V or 2x0.5V=1V its fuckin 2V! Holy shit.

jason9

7 years ago

Yeah. Each cap is rated for 1V. Two in series gives a new cap with half the capacity but a rating of 2V. In series you can charge up to 2V. In parallel you can charge up to 1V. 2F charged to 1V is 1J. 0.5F charged to 2V is 1J.

jason9

7 years ago

Isn’t capacity CV^2/2? (0.5)(2)^2/2=(0.5)(4)/2=2/2=1. (2)(1)^2/2=(2)(1)/2=2/2=1. Series stores as much as parallel as long as each capacitor is charged to the maximum voltage it is rated for.

hurz

7 years ago

@2cent, i have never meet a person whos more stubborn then you. Its unbeleaveable. It comedy what you made here the last days. Thanx for that.

jason9

7 years ago

@hurz, you sure your use of the word never is justified here? Your basically saying he’s more stubborn than @thebugger, an amazing feat of stubbornness.

2ctiby

7 years ago

@jason9 ... The "rating" refers to how much voltage "could" be dropped across the cap without damage ... so if we were to apply 1v across it, then we would get a charge Q of 1 Coulomb (Q=CV). In our described setup of two of those caps in series, the Q is thus halved as being 0.5 Coulombs (which we all agree with)... we are still applying the 1v battery supply across the two in our setup. We have to work backwards from there, because that agreed 0.5 Coulomb charge Q does not then alter. So ... with Q=0.5 and a single cap =1F we get Q=CV ie: 0.5= 1 x V ... so V=0.5 volts for that cap. The main point to note here is that the V alters to suit that equation. Note: Although the cap "rating" may be 1v before damage, it does not mean that the cap will automatically be taking 1v ... Likewise, the volts across our second cap is also 0.5v ... making a total circuit voltage of 1v, as per battery supply. You have confused the volts damage rating with what is actually happening in our circuit here.

2ctiby

7 years ago

@hurz ... your original presentation showed a battery of 1v for the series circuit, connected across the two 1F series capacitors. That is the description which I have referred to throughout. You have now altered that so that the 1v series battery is no longer there... Your sly action is to avoid being seen as having made a wrong calculation for the series total energy. Put it back to that original and so face up to this discussion, otherwise your alterations there will be viewed as a deception.

hurz

7 years ago

if it was ever 1V, then it was wrong! I always calculated with 2V and you always called me and @jason9 are "wrong" with that. @2cent you are comedy! Please go ahead and entertain us

2ctiby

7 years ago

Users all note ... This is the first time that hurz has ever admitted that he was wrong. It is a good step forward, but a pity that it came with an insult to my correction rather than an appreciative thanks. Try that next time Hurz, everyone will appreciate you more for it.

hurz

7 years ago

You telling us now since 3 days it must be 1V, sorry whos wrong, lol?

2ctiby

7 years ago

@hurz ... you declared that the parallel and series configurations (originally shown with identical battery and caps) would hold equal total energy.... I pointed out that you were wrong with that. Just accept that you were wrong in there. ... You should not have used 2v for that series calculation, or you should have altered the series schematic battery to be 2v instead of your shown 1v ... I correctly pointed out your mistake ... Don't try to throw that back at me now that you can see that... just back off with dignity.... I am not kicking you or mocking you for your simple mistake.... but I don't intend to be kicked for pointing it out to you.

2ctiby

7 years ago

@jason9... think hard now about stubbornness, usually it is just a matter of drawn-out debate until things are clarified. You ought to give @thebugger far more respect... he is one of EC's greatest assets.

jason9

7 years ago

In the case of drawn out debate until things are clarified that lasted over a year for @thebugger. He went years thinking that “0.1% distortion going through an amplifier with a gain of a hundred gives a distortion of 10%” before it finally got clarified where he went wrong. I’m not saying he’s dumb or anything, just a bit hard to convince when one of his ideas happens to be incorrect. And to summarize this discussion what @hurz was saying is that two 1F capacitors pre-charged to 1V put in series or parallel when discharged produces the same amount if power, while you were saying that two empty 1F capacitors in series or parallel have different amounts of energy in them if you charge the capacitor bank as a whole to 1V. But that only works because in the case with lower energy it’s because it has the capability to be charged further. This whole discussion seemed to be fueled by a confusion between the two of you and what exactly you were talking about. Both of you seemed to think you were talking about the same thing when you seemed to be talking about things slightly but crucially different and that fueled this whole discussion up until now. Have I summarized correctly?

hurz

7 years ago

@2cent Thats in your sick head. I never declared to keep the voltage as low in series as in parallel. Read this thread again. You are constructing something which was never declared by me or jason. Read what jason9 said in his experiment and come back. Your fantasy gets crazy. @2cent you seems to have problem in reading and understanding. Dont be stubborn and just say sorry jason sorry hurz it was my fault i cant read.

hurz

7 years ago

@jason9, you can take yourself out of this discussiin, but @2cent said we both are wrong.

2ctiby

7 years ago

@hurz ... you had an original schematic presentation of 1v battery for both parallel and series, you altered it, eventually half-admitted that you did, and now deny it ... there is no more to say.

hurz

7 years ago

the circuit is as it is now for 3days and did not changed. You told us we are wrong with 2V and we told you are wrong with 1V but you cant stop that shit. dont blam us for yout fault. Thanx for making the clown the last three days and even take jason beside to explain him why it must be 1V. It was toooooo funny @2cent messy

2ctiby

7 years ago

@hurz .., Many users will have seen your original link schematic showing a 1v battery on the series circuit (to which your 2v calculation was incorrectly used). Your typical lies of denial will not fool those who saw it. Even though some users may not understand the details, they are seeing your lie when you deny having had a 1v battery on that original link of your series circuit.

2ctiby

7 years ago

@jason9 ... you agreed to the 0.5 Coulomb charge etc but cannot follow through with the 1v battery discussion ... Did you or did you not see 1v battery on his original hurz series schematic? If you did, then what mathematical energy can you describe for that total circuit?

hurz

7 years ago

i told you the calculation is what is prior and not the curcuit. The calculation with 2V !!!! While YOU continue to ignore that and told us again and again its your stupid 1V. Nobody agreed to your idiotic 1V but you started to explain us why this 1V must be correct and you failed. You talking since three days of 1Volt its your problem. We never talked about 1V. Shut the fuck up and go and mess in you own circuuts. We are all at 2V or if you follow electronic its 5.4V idiot!

jason9

7 years ago

@2ctiby it’s perfectly fine to charge the series circuit to 1V. It works just fine, but it can be charged to 2V without exceeding recommended voltages for the capacitors, so that’s why we’re doing it at 2V. If you want to find the capacity of a capacitor bank, why measure it at a lower voltage than fully charged? The point here is not whether the circuit said 1V or 2V, it could easily have been an error that never got fixed. It’s about the storage capacity of two capacitors in series vs parallel. If you want to measure them both at the same voltage, then fine. If you want to measure them both at fully charged, then also fine. But know the difference.

2ctiby

7 years ago

@jason9 ... Did you ever see 1v battery on that hurz series section?... yes or no is all I am asking of you.

hurz

7 years ago

No he has not seen this phantom voltage. But he has seen the calculations and he followed the experiment. Only he did a stupid mistake and calculated the capacitance for series wrong to optimistic. ViolationMad and YOU havn't seen that but I have seen and told jason. Cuz i followed his experiment. While you did not followed this topic and talking since 4days bullshit. We are all wrong in using 2V it MUST be 1V. Now you have seen this at my circuits but you havn't followed my calculation. Stubborn, right. Mega stubborn. Go and learn how to calculated with capacitors and shut the fuck up.

hurz

7 years ago

@2ctiby, and even it was 1V in the circuit, i repeat myself, were have you been and told me there is a mistake in your circuit? Were? You always talked about a wrong calculation with 2V and i must set it to 1V. Which we all know is wrong! You said "The total voltage in each of your schematic circuits should be 1v as per each battery ... not the 2v which you have used in your Serial calculations." So what does this mean. You are really a troll.

2ctiby

7 years ago

@hurz ... You had a 1v battery across your link series schematic, with a 2v in its accompanying series calculation. See my first reply above, just under your link there. You either needed to use 1v instead of your 2v in that calculation, or alternatively keep the 2v in that calculation and alter that series battery. ... you did then alter your battery, but denied that your original 1v battery was wrong for your shown calculation. If you now put the 1v series battery back where it was, you will see why I have been persistent ... the series total energy would be 0.25J because a 1v battery would be used in your series calculation, not the inappropriate 2v which you used. The parallel total energy of 1J would then be seen as greater than the series total energy result, having used all similar components ... including a similar battery voltage. ... All you need to do is acknowledge this, and then we can lay it to rest.

hurz

7 years ago

you persistent cuz you are an idiot

2ctiby

7 years ago

@hurz ... and what is your total energy for your 5.4v series battery circuit?..

hurz

7 years ago

how many times more you are going to messup foreign threads? You are the chaos in person. I were to much concentrated in finding bugs i make. You comoletely lost the red line of this topic and finaly you failed in explaining your glorious 1.000Volt. You are a looser and better cincentrate in your personal problems. This thread is closed as nobody will find your 1V and listen 1Joule = 1 Joule this should let you think for a while and maybe you read this topic again to find out what it was all about. @sshsslfun, has some caps which are lilited in its voltage before they get damaged 2.7V max! Building a power bank is easy but needs voltages above 2.7V but till this point you are not able to follow. Put two of those caps in series gives us the ability to charge them upto 5.4V this is what you never understand, cuz you are fixed at your 1.0Volt LOL. If you have anything useful for this thread and nothing were you look stupid let us know otherwise please shut up. Nobody want your 1V

2ctiby

7 years ago

@hurz ... and what is your total energy for your now shown link 5.4v series battery circuit?..

hurz

7 years ago

@2cent, you and electronic will never come together. Its not 5.4V but this i better explain to somebody with a sense of electronics. Go an mess somewere else.

hurz

7 years ago

the same as we would have it organized in parallel with 2.7V, funny right?

hurz

7 years ago

and that was the message for @sshsslfun he made something wring with his capacitor calculator he found on thr web. But you must enter this thread to do us the clown.

hurz

7 years ago

@2cent, would you please stop mess up this thread

hurz

7 years ago

mess in your own threads TROLL

2ctiby

7 years ago

@hurz ... and what is your total energy for your now shown link series caps, 5.4v battery circuit?.. your link is there above here for all to see with its shown 5.4v battery across two 1F resistors at this time. Show the calculation and notice that the presently shown 2v does not work, just as it did not work for your 1v before your 5.4v alteration.

hurz

7 years ago

🤧

hurz

7 years ago

you delete comments? you stink @2cent

2ctiby

7 years ago

@hurz ... and what is your total energy for your now shown link series caps, 5.4v battery circuit?.. your link is there above here for all to see with its shown 5.4v battery across two 1F resistors at this time. Show the calculation and notice that the presently shown 2v does not work, just as it did not work for your 1v before your 5.4v alteration.

hurz

7 years ago

🤧

hurz

7 years ago

@2cent you stink

2ctiby

7 years ago

I am happy for anyone and everyone to discuss the hurz 'series total energy' calculation for his 5.4v battery across two series 1F caps circuit as shown in his present link above here .... along with his similar denied 1v battery circuit .... but by that I mean: "the mathematical calculation of total energy there for the caps" ... hurz is reticent or unable to present his case for that .... and his response has so far only been abuse.

hurz

7 years ago

Doesn't look like you have a valuable input for this thread, cuz you do not understand what @sshsslfun wrote? Read it again

hurz

7 years ago

🤧

2ctiby

7 years ago

@ fraudz ...You are trying to tell @sshsslfun how to configure a bank of caps when you don't even understand two in series ... No wonder you are always using the word "fraud" ... you are the biggest fraud on EC ... your name from now on is "fraudz".

2ctiby

7 years ago

@jason9 ... Did you ever see 1v battery on that hurz series section?... yes or no is all I am asking of you.

hurz

7 years ago

no it was 2 x 8 in parallel, idiot

hurz

7 years ago

read first then ask, messy

jason9

7 years ago

No, I didn’t see. But it shouldn’t matter if it’s there or not. The laws of physics doesn’t depend on the presence of a certain voltage in a certain simulation. It doesn’t matter. It could easily have been a mistake. What’s your point about the presence of 1V in this circuit anyway?

2ctiby

7 years ago

@jason9 ... The voltage across series capacitors does matter. ... a 1v battery gives 0.5v across each of the two 1F caps, and that gives an energy for each cap of 0.125J ...making the total circuit energy stored by the two similar caps 0.25J ... A different voltage instead of that 1v will not give that same result and will need to be worked out appropriately. Hurz presented a 1v battery in his above-here link series schematic but used 2v in his calculation there with it. He then altered that schematic battery and denies having had it shown there as 1v. He then continued with abuse throughout this thread. You obviously need to learn about series cap energy before siding with hurz here, and tell us also what you think the total stored energy of the caps in that hurz-link series circuit would be with a 1v battery and then with a 2v battery, and then with a 3v battery... show your calculations.

hurz

7 years ago

I presented it with 2V in my calculation. The circuit was made for @sshsslfun, cuz he was looking for a field of application. And @jsaon9 does not need help how to calculate the energy in a cap bank. This is not @jason9 thread, its the thread of @sshsslfun. Read first then ask, Mr @2cent messy. @2cent you just looking here for fights. You are a disgusting person. Unfortunately messup every thread you enter.

2ctiby

7 years ago

You had a 1v battery in your schematic and used 2v in its calculation. I pointed out that inconsistency and received only denial and abuse from you. Your schematic was not there aimed at sshsslfun, it was entirely your own effort to say that parallel was the same as series for total cap energy, based on @jason9 two 1F caps idea. You should have had a 2v series battery to demonstrate that point properly. You hadn't thought through that similar batteries will not do that there... hence your 1v series battery. Then you srarted the abuse and deception.

hurz

7 years ago

you got abuse and denial because you continued with 1V instead of use 2V. Dont you get that? You continue for 3 days to explain something with the wrong voltage 1V and cant stop. You gave us all the clown.

2ctiby

7 years ago

There is no more to say to you hurz. I have made it clear that your link series schematic and its calculation were inconsistent as per my descriptions. If I were to continue, it would just be "casting pearls before swine". You, no doubt think that the last word means a 'win' ... so go ahead, but others have seen what is what here.

hurz

7 years ago

I came here to tell @sshsslfun about an idea what he can do with all this caps. YOU CAME HERE TO MAKE TROUBLE BUT ENDED AS CLOWN

sshsslfun

7 years ago

What here is true??

hurz

7 years ago

read the thread, if comments are to long then just skip them 😋

sshsslfun

7 years ago

Alright, thanks 😄