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bryanthehacker
modified 9 years ago

Simplest 0-10A Buck Converter

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1d 00:17:42
50W Buck Converter 0.4% ripple voltage Semi Perfect Square Wave Modulation No IC Automatic FM and PWM Mosfet IRF9540 (Low Rds) Zener 1N4734 (or a LM7805 with a diode between ground pin and ground) Transistor BD139 and BD140 Full Load Efficency Eff = Pout / Pin Pout = 5v * 10A = 50W PWM = 5v / (10.5 - 1.78) = 0.573 Pin = 12v * 10A * PWM = 68.8W Eff = 72.6 %
published 9 years ago
WTFCircuit
9 years ago
It's more around 74%
nikisalli
9 years ago
I'll build this
Antonio1961
9 years ago
nice
thebugger
9 years ago
Around 72% efficiency but that's still very good keep it up. You upload nice circuits
bryanthehacker
9 years ago
Thanks Bugger :)
2ctiby
9 years ago
http://everycircuit.com/circuit/5320403804749824
bryanthehacker
9 years ago
@thebugger i increase circuit efficency placing a signal amplifier for the p channel mosfet
WTFCircuit
9 years ago
Another tip, do never use diodes in parallel to increase the current that they can support, it is more likely to burn them
thebugger
9 years ago
Bryan usually a driving stage will improve the efficiency slightly by driving the transistor harder from on to off and vice versa, but the primary use of such a stage is to limit the peak current draw from the gates of the MOSFETS, or more precisely to increase the accuracy and Slew rate of the pulses that drive the transistors. Most MOS transistors have a high gate capacitance, and when driven sharply with a high frequency pulse, the capacitance distorts and dampens the driving signal, thus not opening fully on, or not closing completely when prompted. WTF is right, it's not wise to use diodes in parallel unless you've taken measures to even out their parameters.
thebugger
9 years ago
One thing I can recommend is to give the overshoot some consideration. For instance for keeping a low overshoot factor you need to choose a filter whose characteristic impedance is lower than the load (Zo<Rl). For instance your filter has a characteristic impedance at half of that of the load. It's best if you use a critically dampened filter, which has an impedance of 1/10th of that of the load. Basically you have to stick to high capacitance low inductance. For your load a good filter would be around 6.5uH for the coil and 2.2mF for the capacitor. Also add some resistance in series with these components. Like 10mOhm for the cap and 50mOhm for the inductor to represent their ESR. This can't always save you from a potential overshoot but it's a good start. You can take it even further with an overshoot protection with a floating regulator. If you're interested I'll show you how to do it. Keep it up.

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