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zorgrian
modified 4 years ago

7 Mhz Direct Conversion Receiver. Double Polyakov Russian 4DPD 4-diode product detector mixer. Able to detect AM SSB CW and other modes.

5
9
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07:46:44
/radio/receiver/double polyakov/direct conversion/ Note: This is a revised version of a mixer that I posted some time ago but this one is working at 10 MHz NOTE: GIVE THIS SIMULATION SOME TIME TO SETTLE DOWN This is the business-end or main part of this direct conversion receiver. The important point to note here is that this receiver is 'tuned' by injecting half the desired frequency into the mixer. In this case we can use a triangle wave. So the difference between the two input generators produces a 10Mhz carrier which is Amplitude Modulated with a 500 KHz modulated AM signal. Although its not possible to hear 500 KHz this is done in the simulation in order to test this product detector. (Thanks to @hurz for providing the simplest method of generating an AM modulated tone in EC.) The Polyakov detector is interesting, as it uses a frequency of half the frequency that you are tuning into. This is useful as it potentially allows for a far more sensitive receiver. Higher sensitivity is obtained by lowering the risk of undesirable products from the VFO..... The normal arrangement for the Polyakov is just two anti-parallel switching diodes, and then there is a low value 500 ohm preset pot that does not seem to do anything other than serve as a voltage divider, which I don't like much. So here, we have two sets of Polyakov detectors back to back. No useless pot! Unlike the original, the input is terminated with 1K ohms and the LO frequency is injected into the centre of the diode arrangement. A crude filter network removes much of the 5 MHz LO and 10 MHz received signal and allows us to see the demodulated 500 KHz signal that is recovered. Unlike balanced diode mixers this mixer does not require large input signal levels. In fact one has to be quite careful not to overdo it. Note that I mean that high levels are not needed on the RF input side. Whereas, the LO side can be 3 - 5 volt logic square wave! It is suitable for a low cost multi band receiver Note that in an attempt to prove that this mixer is indeed operating as a switch that works twice every cycle, and not some weird subharmonic heterodyne explanation that floats around the internet, I have used a square wave LO, which is fed into the mixer and a completely acceptable output results. This mixer is very easy to build, does not require any complex transformers and is able to retrieve SSB CW and AM (so maybe there is some small truth in the heterodyne argument, as the only other simple receiver able to do this is a regenerative receiver - i.e. using the double Polyakov, no insertion of the carrier frequency is needed to recover SSB using this mixer. In a regenerative receiver the carrier insertion is done by the LO which is the regenerative oscillator itself ) In reality this mixer can be used for all the HF bands (with appropriate changes in the capacitor values and the LO frequency. Enjoy 73 Fine business! P.S I now invite all sorts of comments even if they may be negative, or way off the mark. I even encourage comments from persons who have no idea what I offer here but would like to demonstrate how wrong it all is etc....
published 8 years ago
jason9
8 years ago
If you use a JK flip-flop with the delay set to 1nS to halve the input frequency and feed its output to the mixer/demodulator, and remove the 9.5MHz source and then look at the bode plot, you will see a spike at 500kHz. That's the only reason that this circuit appears to work. You can fix this by decreasing the resistor on the far right to 20ohms. Although it might seem like a low value, it doesn't use much current compared to what's going through the mixer/demodulator.
jason9
8 years ago
Another option is to decrease the capacitors on the left except for the leftmost one by a factor of 1000 and decrease the three capacitors on the right by a factor of 100. If you do either this or decrease the resistor then you will have to increase the input signal.
jason9
8 years ago
Oh, I almost forgot. If you choose the second option then you will also have to increase the inductor by a factor of 100.
zorgrian
8 years ago
@jason9 I have not done a repeat of the proof that you suggest; that might indicate that this circuits ability to recover AM is an anomaly (of what though?) Here is an earlier version...but note that in this version the circuit and the filter is designed to retrieve an AM signal of 5 KHz not 500 KHz. http://everycircuit.com/circuit/5544964524343296 Perhaps you could share your discovery? I am interested to see what your circuit looks like.... Standing by... Fine business 73
zorgrian
8 years ago
Oh, I almost forgot. I do concur that the filter has a 'spike' on the bode plot at around 500 KHz. This is quite normal. However, the filter is only in the circuit to allow sight of the recovered signal. I maintain that it is not the reason that this type of detector works. A simpler form of this detector has been used for decades!
jason9
8 years ago
Sorry I took so long to respond, I just haven't checked for a reply until just now. I completely removed the filter and replaced it with a matching 200nS square wave voltage source to get rid of the square wave that the filter is supposed to filter out, and the output is completely dead. No signal at all. I completely left the entire diode system and the three left most capacitors, so the demodulator itself should still function perfectly, except that it doesn't.
jason9
8 years ago
Actually, I'm partially wrong. There is some signal, it simply disappeared because I replaced the diodes with Schottky diodes which removed the effect of the demodulator. I still have to test the strength of the signal, but I suspect that it is orders of magnitude lower than shown here.
jason9
8 years ago
This time, I tested again and left the demodulator exactly as is, without even lowering the capacitor values to make the amount of current more realistic, and I'm having trouble detecting any demodulated signal. I filtered out most of the noise using a couple of square/triangle wave generators and one sine-wave generator to nearly fully remove the carrier and demodulating signal, leaving only the as-far-as-I-can-tell non-existent demodulated signal.
zorgrian
8 years ago
Ok why don't you give examples? Why dont you look into the polyakov mixer on the net? Russian hams have been using this for decades! It has an advantage, that is the LO is at half the desired detection frequency. This minimises bleed through and other birdies

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