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The resonance frequency of all the LC tanks is 88.9 Hz. The amplitude of the input signals are 1, 2, 3, 4 and 5 Volts, respectively. All the inputs are in phase and oscillate at 88.9 Hz.
Play with the switches and try to store some energy inside one or more tanks, which can be wired in serial and / or in parallel to the sources.
Then, rewire the circuit in a different way while keeping the oscillating signals inside the tanks, and observe how the amplitude and / or phase of the signal inside each tank does change.
### HINTS ###
Let the transients do extinguish before rewiring the circuit in a different way (for that, you can monitor the green voltage and wait for no current).
To empty a tank, without restarting the simulation from scratch, you just need to make it floating (no connection to ground).
To set a tank aside, you just need to make sure it has a path to ground and that it is not connected to a voltage source or in parallel with other tanks.
### EXAMPLE 1 ###
Connect one tank to 1 V, let it charge and then set it aside.
Connect a second tank to 5 V, let it charge and then set it aside.
Leave the third tank empty.
The tanks are in sync.
Connect the three tanks in series, apply the 3 V input source and observe the final value of the amplitudes.
The three tanks are still in sync, oscillating at 0, 4 and -1 V.
initial total voltage amplitude = 5 + 1
final total voltage amplitude = 3
delta voltage per tank = (3-(5+1)) / 3 = -1
final voltage 1st tank = 1 + (-1) = 0
final voltage 2nd tank = 5 + (-1) = 4
final voltage 3rd tank = 0 + (-1) = -1
In particular the initially empty tank is now oscillating with an amplitude of 1 V but in opposition of phase (-1 V).
The fact that we can evenly spread the delta voltage over the tanks is because the tanks are identical (or resonant).
### EXAMPLE 2 ###
Try also to change the resonant frequency of two tanks, connect them in series, apply some voltage to them and observe what happens (only the resonant tank will grab the entire signal after a transient period).
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