Something something

01:09:44

 I'm unsure why the switch on the left causes  the  4 less in parallel  to  become brighter  when switch is pressed and current  is flowing through more resistors   instead of just one for all 4.  Is the simulation perhaps  factoring the resistor heating up disapating more current causing  increase in heat/ resistance?

published 6 years ago

BillyT

6 years ago

I think you mean switch on the right, and the answer is, what is the equivalent resistance of 4 resistors in parallel.

j5892000

6 years ago

Yeah you are right about it being on the right. My bad. I just assume that the current would be less when it has more resistors to go though. Don't I just add up the resistors find out the total resistance ? I suspect no only because if I did the result would be less bright leds when current flows through all resistors

j5892000

6 years ago

Msn I'm stumped. Logically that makes no sense. More resists should be more resistance

j5892000

6 years ago

In simple terms I guess in series the voltage has one path so the force gets uses up ... so circuit is more effected by resistances. With parallel there us multiple paths for voltage so it's no as affected by resistances. And current can easily flow. Right?

ClayCube

6 years ago

Resistors in series you add up but in parallel its Rt = 1/R1 + 1/R2 + 1/R3 + 1/R4 which equals 393mΩ

Robert_Kidd

6 years ago

In series the current is the same through all resistors. The voltage across each resistor depends on the resistor value and will be V=I x R. Add all the voltages together and they equal the supply voltage. For parallel resistors the same voltage (supply voltage) is across all resistors. The current through each resistor depends on resistor value and will be I=V/R. Add all the currents together and that will equal the total current from the power supply.

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