modified 7 years ago

A simple oscillator.

00:56:23

Very simple oscillator. 

published 7 years ago

GuzenkoVladimir

7 years ago

DC voltage. Try shake you Phone

BillyT

7 years ago

The main problem is that the capacitor is changing through a very large resistor and the time base is set far too slow to show the charging event, a secondary problem is that because there is no switch in the circuit, the capacitor, by default is assumed to be fully charged by EC when you start the circuit. Thirdly, the capacitor would need to be discharged at some point in time. Try; http://everycircuit.com/circuit/6590847750766592

tonyinselby

7 years ago

You have an enormous capacitor charging through an enormous resistor. The time constant τ for the combination is 5,546. This means that it will take some 1½ hours for the capacitor to charge to 63% of the applied voltage, or around 7¾ hours to charge to (conventionally) "completely charged". The timebase can't be set slow enough to see this.

gbhmage

6 years ago

The resistance and cap can be changed. It was just an example of a really slow oscillator

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