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jason9
modified 7 years ago

Question

0
6
56
01:27:12
I measured the power usage to be 15.4-15.3W while the bulb uses only 15.1W. Where's the power loss?
published 8 years ago
ian7
8 years ago
Heat
BillyT
8 years ago
Choke & amplifier?
rich11292000
8 years ago
16.9w input. The input voltage is square wave, its form factor is 1. The inductor is experiencing a sine wave, its form factor is .707. Also follow the electron animation and see the cap is using more current than the bulb.
jason9
8 years ago
These are perfect components (except for the 1uOhm resistor but that's so small it doesn't matter), so I'm having trouble seeing where the power loss is. The amplifier has 100% efficiency and when giving out a positive signal current is always coming out of it, never going in, so I don't have to worry about the current going to the negative supply while it's giving a positive output. Any power that seems to get lost in the LC system is just going to come back out because neither inductors nor capacitors can be a source of dissipation unless they are imperfect which they are not in this simulator.
rich11292000
8 years ago
FOLLOW THE ELECTRON ANIMATION AND SEE 2 AMPS FLOW THROUGH THE CAPACITOR, YET .1 AMP FLOWS THROUGH THE LOAD.
jason9
8 years ago
But capacitors don't dissipate energy like resistors, they store it and release that energy when the current starts flowing the other direction. Same thing with inductors, and then the energy just bounces back and forth between the two, building up with the help of the amplifier until enough energy is built up that the amount dissipating through the load is equal to the amount going into the LC tank. Capacitors and inductors simply don't dissipate energy. If you built an LC tank circuit and gave it some energy, then you would see that the energy just keeps bouncing around between the inductor and capacitor. Even if it does eventually die down, that's just an imperfection in the simulation.

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