HELP

Ponlas en seriw

Serie"

English please

Put the lamps in series!!!

doesnt work in current hehe

For the current going through to be acceptable you need bulbs with a higher wattage or power rating for a given voltage. Or more reasonable would be a current limiting resistor if it was a constant voltage supply.

First, get rid of lower circuit with current source. Looking at other circuit, you have 29V supply and two 12V bulbs, so you need to drop the extra 5V across a resistor. Note: you need to select each bulb in turn and adjust its parameter's so it IS a 12V and 1.5W bulb. Work out the current the lamps will take. For 12V and 1.5W the current is 1.5/12=0.125A or 125mA. As resistor must drop 5V and pass 0.125A, it's value is 5/0.125=40 Ohm. If anything is unclear please ask. If you choose to put lamps in parallel you will need a resistor to drop 17V. With each lamp taking 0.125A, total current is 0.25A giving a resistor value of 17/0.25=68 Ohms.

A quien le importa si no funciona en corriente por lógica pon un filtro de capacitor y resistencia y en el otro solo en serie y listo!!! Woow no es tan difícil!!!

http://everycircuit.com/circuit/6411604252164096

Hi @FernandoCPF, I am not sure you read the question thoroughly before you answered :-)

Amused

Ditto.

@robert, @chris, note the resistor will need to drop the voltage by 5 volts, and have .125 amps of current through it, so the power dissipated is 5*.125=.625 watts. So make sure you have a resistor with that wattage rating or higher, probably be easier to find a 1 watt 40 ohm resistor. This will keep you from burning up a resistor.

Absolutely, thank you.

Put the source at 200mA

No put the source at 100mA. Coz your lamp is about to blown up.