AC to DC converter with step-down

1842

1d 17:10:37

Take a 240V 60Hz AC source and convert it into a 12V DC signal.

The 4 diode bridge restricts the current flowing backwards, giving you the half-cycle DC waveform. The 2 capacitor in parallel & single inductor acts as a filter that gives you that almost flat DC signal. 

Expect the voltage at the lamp to be slightly lower than 12V, because of the diode's small resistance and the LC reactance.

published 12 years ago

normhayashi

11 years ago

LC Values: T/100. T=1/f=1/60Hz=16.7ms. 16.7ms/100=167micro Farads/Henries.

waynewec

11 years ago

Take the ground connection off the bottom of the secondary - what you currently have is only a half wave rectifier

ASONI

11 years ago

All right ...!!!

sungeneral

11 years ago

No, not everything. Sin wave with amplitude 240 volts is not 240 v AC. For 50 hz you should multiply 240 with square root from 2, don't know how with 60hz. You can google what's difference between effective value and voltage amplitude, in mains you have effective value 240 volts.

sungeneral

11 years ago

I found http://en.wikipedia.org/wiki/AC_power#Real.2C_reactive.2C_and_apparent_powers

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