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thebugger
modified 10 years ago

Amps for Jason

9
8
337
04:39:05
The only thing that differentiates the different classes of amps (A,B,AB) is the idle current of the output device. In class A (blue) the idle current is always set at 1/2 the Icmax, so the output transistor is always dissipating 1/2 the maximum power. That's why it only has 50% efficiency and that's a theoretical value. Often it's much lower, and sometimes when you're listening to music on low volume it can fall down to single digits. The maximum theoretical efficiency can be reached with transformer coupling. These amps sound the best because the output transistor is always in a conductive state e.g. it always stays in the linear part of its characteristics. Now class B is a whole other story. It contains two putput devices, one for each half cycle (negative positive). When no signal is applied it doesn't draw any current and that's why it has much higher efficiency (78.5%). But as it is with class A, that value is rarely reached. These amps have an inferior quality compared to the class A counterpart, because one of the output transistors is always off, thus introducing non linear distortion. Moreover class B amps have a so called crossover distortion, that occurs around the 0V point, when neither transistor is conducting. That can be fixed by slightly biasing them (a few mA is enough) and through a negative feedback. Now class AB (yellow) as the name stands combines the best of both. It has the quality of class A amps with the efficiency of class B amps. That's done by biasing a class B amp deeper into the class A region. For instance instead of a few mA idle current a class AB amp can be biased at a 100mA idle current. This way, at low audio levels, the amp will work in class A mode, and after you've reached the 100mA threshold it'll take it to class B mode, but at higher power levels where the crossover distortion is negligible. Just remove the signal sources from the amps and observe the idle current which they draw. Now for the other classes which i haven't displayed. Class G and H are not widely acknowledged by the scientific community, because they're a variation of the other classes. For instance class H is actually a class B amp modulating the supply rails for class A amp. The efficiency isn't great but is much improved. Class D amps are a whole other story. They do not use analog amplification. They use PWM as the driving component for an LC filter which restores the signal. The main reason why they're so efficient is because the switching component has either ni voltage drop with maximum current through it, or a maximum voltage drop, with no current through it. It's tough to explain, but as you know the Power is IxU, which means either 0VxImax or 0AxUmax, so the dissipated heat is ideally nonexistent. But in reality efficiency levels of 95% are normal. The active devices can be viewed as switches
published 10 years ago
jason9
10 years ago
I still don't understand why the efficiency can't get above 78.5%.
thebugger
10 years ago
Well mathematically presented let's assume a completely lossless circuit. You have 20V power supply and a 4ohm load. So you get 20x0.707= 14.14Vrms The current through the load is 3.5Arms. The output power will be 50Wrms. The drawn power however isn't 14.14Vx3.5 but 20Vx3.5=70W. The maximum efficiency then is 50/70x100=71% I should point out that the average current for the source is more accurate than the RMS current. So the equation actually looks like this. 20V/4ohm=5A 5Ax0.636=3.18Aavg 20x3.18=63.6W so 50/63.6x100=78.5% efficiency. And this is in a completely lossless circuit. If you take into account slight biasing, voltage drops from transistors, insufficient gain therefore some damping and many other factors you get a typical efficiency ranging from 50-70%
jason9
10 years ago
But with a square wave the average voltage is the same as peak voltage and same for current thus 100% efficiency. Am I right?
jason9
10 years ago
Which is why class-D amps have a maximum efficiency of 100%.
thebugger
10 years ago
Class D efficiency is harder to calculate because of many many factors, but an approximate value can be easily estimated. The efficiency comes from the fact that the MOSFETS theoretically dissipate no power in heat losses, because they can be viewed as switches. With class B amps we determined that the power supply and the output difference (RMS difference) is dissipated as heat. For instance the power supply is 20V and the output is a maximum 14.14Vrms. The difference of 5.36V is dissipated as heat from the transistors. With class D amps the output is always either equal to the power supply (no voltage drop) but with maximum current or it has a maximum voltage drop, but with no current flowing through the MOSFET. So theoretically 0V*Imax or Umax*0V wll always equal 0W dissipated from the transistors. In reality the switching time, the rise/fall of the PWM and other factors lower the efficiency to around 90-95%.
jason9
10 years ago
So, does that mean I'm right?
thebugger
10 years ago
Partially yes. The efficiency is a complex number that can't be viewed just by looking at the Pout/Pin. There are many other factors too. But yes, because there isn't a RMS difference the transistors can drop, all available power goes to the load.
jason9
10 years ago
Thanks for the information.

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