EveryCircuit - Short circuit protection circuit for battery charger

2ctiby

5 years ago

Not really a protection while there is 12kA flowing when the right button is held down.

kiani

5 years ago

It protects the Led s, by exploding the voltage source.

2ctiby

5 years ago

If the 1m Ohm resistor is meant to represent a fuse, then the red light would not stay on when it is blown.

diggu

5 years ago

Resolved ...please check

kiani

5 years ago

10A through the coil of the relay,.. At the press of a button., and 6KA through press of the other button.. The circuit is a killer.

kiani

5 years ago

I don!t have solution , for this cct...

diggu

5 years ago

तुहर समझ के बाहिर हे।

kiani

5 years ago

Nice writing, i hope its not rude. Lol

PrathikP

5 years ago

I don't think it's beyond anyone's understanding you coward

kiani

5 years ago

Set the sim speed to 100us/s it doesn't work any longer, plus the 6KA killer current through the fuse still there.

kiani

5 years ago

12v 10 mA Leds, interesting...build the circuit and see what it does for you.

diggu

5 years ago

Ok but its like 10 Amp CIRCUIT BREAKER

2ctiby

5 years ago

@diggu ... yes nice ... it's working fine now after your alteration. If the white lamp is shorted, then the relay drops out and shows a red LED, rather than waiting for the protection fuse to blow.

diggu

5 years ago

@2ctiby .....thanks

diggu

5 years ago

1k resistance series in 2v leds (I'm not putting it because circuit gets tangled

kiani

5 years ago

Yes the relay contacts sieze up after a 6 KA current spike and according to exoert no knowledge 2ctiby, "nice".. The relay setting is incorrect. The EC relay default setting is for a 5 volt rrlay.... 2ctiby have you ever build a circuit!? ,, !

LeButch

5 years ago

This circuit is a genious piece of design. Really really well solved.

2ctiby

5 years ago

@diggu ... You would still need to be careful to not press the reset button until after the short is fixed, otherwise it would blow the fuse. A switch instead of a button to simulate the lamp short would show that. ....... a project worth working on.

diggu

5 years ago

Resolved - R value increase to 250mohm = 1 ohm 4 R in parallel

kiani

5 years ago

Great solution, lol,, just bypass the fuse..

kiani

5 years ago

The low value resistor indicates its a fuse,, maybe anti surge fuse would help, don't know.., the relay setting still wrong,.

2ctiby

5 years ago

@diggu ... Leaving the lamp short in place (which could be simulated by using my suggested switch), will show that the circuit current is 12kA whilst the left reset button is pressed down ... Making the fuse thicker will not stop it blowing with that level of current. You need a way of ensuring that the reset button can not work until after the short is disconnected.

2ctiby

5 years ago

@diggu ... In your shown circuit, the button on the right cures the shorting as soon as it is released, but a real short may stay put more like a switch there instead of a button.

kiani

5 years ago

A switch instead of the lamp is not rroresentative, cause its going from nothing ampers to 0 ampers {on EC, instantly} ehich is not possiblr in reality.. There will be arch before short hapoens, at the sight of the first excessive current an overload is reached and hopefully a circuit ( not this one) will trip. As is the circuit should trip with over load, but it only activates the relay with a dead short.., { the relay setting is wrong. As well, which does not help).... hope my txt. Is comprehensive enough.

2ctiby

5 years ago

@kiani ... My switch depicts a retained short across the lamp, to make the point that the left button must not be pressed whilst that short is in place ... Your usual confusion only makes things more difficult.

kiani

5 years ago

I see, yes if its reset with short in place, , anyway this cct. Is disastrous.

diggu

5 years ago

@2ctiby.....Resolved please check

2ctiby

5 years ago

Good, it's nice when things are understood without abuse, or determination to have been right regardless of new insight.

2ctiby

5 years ago

@diggu ... keep an eye on the current shown through the battery or the resistor above it there... Are you happy with the seen 48A whilst the button is pressed during the resident closed switch shorting ?

kiani

5 years ago

Chek this,, it should be comprehensive enough. http://everycircuit.com/circuit/5534503796473856

kiani

5 years ago

You are begining to sound like Len...ul. 2Ctiby... First one needs to understand that they don't understand, before they can actually understand,,,, most humans don't like it,, and think, and find it defametory to give up ignorance.

2ctiby

5 years ago

@kiani ... you are not beginning anything... you are just continuing to to sound like the senseless idiot that you always have been on EC... Your link still puts 48A through the battery when the reset button is pressed whilst the lamp short is in play.

kiani

5 years ago

Correct about my link,, i redrew, unmangled the cicuit so you can see better.... You are looking for negative.. , try harder you might, just might see positive,

2ctiby

5 years ago

I might just .... hope springs eternal ...

diggu

5 years ago

This circuit is working in the same way as circuit breakers, it is also a short circuit protector and it also takes a lot of current during short circuit.

diggu

5 years ago

And that too for just a few ms

2ctiby

5 years ago

Yes ... but in your design here, there is a danger of sustained high current if the left reset button is held down whilst the short is resident.

diggu

5 years ago

Release it after pressing the Reset push button because it is a push button not a switch, such as DOL Starter start button

diggu

5 years ago

This circuit would be dangerous but is fine for low current circuit. Like battery charger

diggu

5 years ago

Those who are not satisfied with this circuit, check this circuit by making it in the bread board.

2ctiby

5 years ago

Releasing the button quickly sounds fine, but not all users may consider doing that. If they, for any reason keep the reset button held down, then a dangerous current will be held on. On a breadboard 12v little battery there may not be a major problem, but if the 12v is a car battery with this setup then it probably could be a big problem.

diggu

5 years ago

Ok, this circuit will only work on low current .... now happy

2ctiby

5 years ago

It's not a case of being happy. It is a case of all agreeing what is happening in a circuit.

badassfromaus

5 years ago

Diggu don't be disheartened by what has been said your circuit is ok you don’t need the resistor because it’s shorted out till you fixed the short not needed. I only made the one I did because it’s a problem having to reset each time you turn power supply on and I was thinking of making it. Keep on doing what you are doing hope you enjoy this hobby take care. http://everycircuit.com/circuit/5463064296816640

2ctiby

5 years ago

@badassfromaus ... I am all for encouragement as you can see from my comments above, eg "nice" etc. But you as well as diggu need to see that 13.8 thousand amps flow through the badassfromaus battery when the button is held down whilst the closed short switch is enacted.... That is an issue which can not just be ignored. If you claim that a fuse would blow, then why have a relay etc extra to the fuse. ... good luck to both of you in enjoying your endeavours.

diggu

5 years ago

@badassfrommaus....But even in this circuit, if the reset button is pressed in the short circuit position then 13kA current flows.

badassfromaus

5 years ago

I have built a lot of power supply's none with the amp's you are talking about most of my circuits are used in everyday uses. Also note a fuse or circuit breaker should be fitted to all power supplies. Any way that's all I have to say.