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eekee
modified 7 years ago

Quadritonic inverter

0
6
245
01:47:33
Digit levels: 0 1 2 3, 1V per level. Truth table: 0 3 1 2 2 1 3 0 Much easier to design than a trinary inverter, but still not as good as binary. It's 1.5-2 times larger than 2 CMOS inverters. I'm basically designing logic series from scratch to make these things, and finding I'm not very good at it (yet). This is a primitive form of this gate design. The transistor thresholds should be adjusted for some overlap in turn-on regions. I'm not too worried about the practicallity of multiple power supplies. Modern computers have voltage converters all over the place. Amusingly, this requires accurate MOSFET thresholds, the development of which enabled the elimination of multiple power rails for binary computers some decades ago. It needed diodes so the level 1 and 2 FETs wouldn't drag on the 0 and 3 levels, respectively. Silicon diodes have too high a forward voltage, and I'm almost sure germanium integrated circuits are not a highly-developed technology,* so this uses MOSFETs with very low thresholds as diodes. There seems to be a problem with the diode for level 1: open the switch. It may not be a problem after threshold tuning. *: MOGFETs, anyone? Metal-oxide-germanium... :) The digit levels are weaker than intended. It might be best to declare the weak voltages to be the proper levels and design accordingly. On-chip size estimation by sum of transistor width: * This circuit:12μm * If diodes for 0 & 1 are P-channel: 16μm * 2 CMOS inverters: 8μm Bleh! lol
published 7 years ago
jason9
7 years ago
MOSFET: Metal-Oxide-Semiconductor Field-Effect Transistor. Germanium falls under the category of semiconductor.
hurz
7 years ago
I think he wishes to have a lower threshold if germanium is used for mosfet transistors. But this is not the case. Mosfet threshold do not depend on semiconductor material. Its a matter of an electric field and the channel dimensions length and width.
eekee
7 years ago
@jason9: MOSFET also means Metal-Oxide-Silicon :)
eekee
7 years ago
@hurz: It needs diodes, the FETs would be on the same die. ;)
hurz
7 years ago
@eekee, explain why you have set the Vth to 100mV ?
eekee
7 years ago
@hurz, minimal dropout voltage

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