Base current

You need to solve two equations to analyze. First one; Vcc= Rb*Ib + Vbe + Re*Ie coming from the left side. Assume a region for bjt, for ex. Forward active(FA). For this region Vbe has approximately 0,7( depends on bjt). Also Ie=(B+1)*Ib, then solve first equation to find Ib ( you now know Ie and Ic too). Second equation; Vcc= Rc*Ic + Vce + Re*Ie. Insert current info to this equation to find Vce. Lastly, check for region assumption, that is, for FA, Vbe > 0 ( approx. 0,7) , Vcb > 0 (approx. 0,5) or Vce >= 0,2 ( approx.). If you want to calculate exactly then use bjt characteristic equations( exact relations between biasing voltages and currents) solve them. Sorry for wall of text :)

See http://www.electronics-tutorials.ws/transistor/tran_2.html ... 'NPN Transistor Example No 1' section on that page....and work from there.

10 - 220kIb - 0.7 - 510(Ib + 100Ib) = 0: Ib ~= 34.2uA

Detailed calculation help here.... http://everycircuit.com/circuit/5697495873355776

Thanks to all of you :)