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thebugger
modified 7 years ago

Breaker circuit

1
21
320
03:47:52
Press switch on the right to simulate shortout. Press switch on the left to release protection after you've fixed the short out. Now that the sensing side is at the positive supply rail, there won't be any problems with ground loops and whatnot. The circuit is just exemplary, might cause some problems with stability in reality, but you get the point. The first top left op amp, measures the voltage drop between the 100mOhm resistor. A perfect indication is not necessary, because the secons op amp works as a Schmitt trigger, and has an adjustable threshold level. The transistor part on the right is a bistable latch Once the schmitt trigger figures out theres a short somewhere it generates a square wave that enables and latches the relay so that is disengages the load. Right now the protection should work at 4.25A. The circuit is open to criticism, I designed it in 20 mins or so and haven't had the time to work out the kinks yet.
published 7 years ago
jason9
7 years ago
This is pretty much how my breaker circuit works, only it has much fewer components and no ICs, the relay is replaced with a p-type MOSFET, and the current sensing resistor is after the MOSFET, not before it, but the sensing side is still the power rail, not the ground rail. The ground rail is untouched. Perhaps you were looking at the wrong breaker circuit (not sure how, but you never know) when you said that my breaker was low-side and that it should be high-side. It is high-side. I’ll provide the link.
jason9
7 years ago
Here’s the link: http://everycircuit.com/circuit/5229068768509952
thebugger
7 years ago
It's not remotely the same. Low side current sensing is way different than high side sensing. The latter requires most of the time to re-reference the voltage drop to ground potential in order work around the issues of combining several parts of the circuit.
jason9
7 years ago
But do you agree that my breaker is high side? And that therefore it’s only effect when latched is a slight resistance in the power supply?
abobaker
7 years ago
How did you come up with that latch circuit ?
thebugger
7 years ago
No, your breaker is low side, and the resistance comes in the ground rail, which is highly undesirable.
thebugger
7 years ago
I just bunched together several blocks into a circuit abobaker
hurz
7 years ago
Have you guys agreed about what circuit you are talking? I see a high side current sense circuit from jason. which circuit is buggzy looking at? Jason have you made a proper description, what is load and what is shunt resistance?
jason9
7 years ago
The 2ohm is load, the 33mOhm and MOSFET Rds is shunt
jason9
7 years ago
We should ALL be talking about the circuit I provided a link for. I’ll give it again just to make sure we all have the right circuit in mind.
jason9
7 years ago
Here’s the link: http://everycircuit.com/circuit/5229068768509952
hurz
7 years ago
So buggzy, do you see now?
thebugger
7 years ago
Ahhh yeah, this one is high side. I was searching for circuit breakers in general in EC, must've gotten a different circuit. Yeah, this one works, and it's nice actually, a lot simpler than mine. I do like relays more than mosfets though in such applications.
jason9
7 years ago
So, this in conjunction with the existing current protection circuitry in my amp should provide adequate protection, right? And if I replace the diodes with that two resistor one transistor biasing circuit and thermally connect the transistor to the main heatsink, then that should counter heat related issues, right? And then my amp would be something you would approve of?
hurz
7 years ago
Why this damn toggle latch? Is there a good reason for this instead of a normal RS latch? I dont think so. http://everycircuit.com/circuit/5394611236503552
thebugger
7 years ago
It's a T trigger latch. Doesn't matter whichever you use.
thebugger
7 years ago
Look, your amp already draws around 15A average. Just place a household 16A breaker. It'd be easier to work with. Anyway there are things on the design that might need improvement.
hurz
7 years ago
Doesn't matter whichever? Its so slow your breaker does not trap at 100+A! Doesn't matter ......
jason9
7 years ago
What things might need improvement? And, what if the mix of harmonics in the audio signal being sent through the amplifier happen to generate a somewhat square wave? Then it will draw say 20A and the amp will still be in its normal operating range.
hurz
7 years ago
Or the amplifier is a buggzy design and starts oscillating and draws 100A+ at 100kHz ... Or a wire shorts and with each short it burns an atomlayer and stops short, cuz the magnetic field moves the wire away, but after a while or 10us it shorts again and this repeats till the farm is burning?
thebugger
7 years ago
Just use a regular fuse.
hurz
7 years ago
Right, thats the propably better solution

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