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zanini007
modified 8 years ago

Constant current with PNP

3
1
154
02:45:42
The current is determined by the resistor at the emitter of NPN transistor and the voltage at the base. But this circuit have a lot of powerloss...
published 8 years ago
BillyT
8 years ago
I initially was going to overlook this circuit as a Newby doing a trial circuit, on checking your information, I saw that you'd been around some time, and I was surprised at the lack of transistor load and biasing knowledge. I am not the world's best of expert, but here is my basic approach. The output circuit is basically current amplifier towards the power supply, (the transistor is back to front, so just turn it around), with the circuit connected and turned on the way it is, the transistor has a gain of 100, so if you want 20 mA output of the drive transistor, it only needs about 0.200 mA base current. Now The transistor that is biasing that transistor on is also being used as a current amplifier, this is good news because the 4 Leds connected in series require 8 Volts to illuminate them, but if you get the current correct the Voltage will follow. So all you need to do is adjust the collector resistor of the biasing transistor to limit the current through it to approximately 0.200 mA. This will also require a base resistor for this transistor to limit it current to approximately 0.002 mA, these values may have to be trimmed a little bit, to allow for the Voltage drops across the transistors. When this is all done, you will find that the circuits output current is set to20 mA, and when you change the number of Leds, it stay at 20 mA. I hope at this point in time I have successfully put a cross the intricacies of transistor gain and biasing. http://everycircuit.com/circuit/5658276237934592

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