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jbasanth
modified 9 months ago

CE Amplifier-Small signal

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04:20:32
The small signal amplifier used here is the low power audio amplifier. Everything is calculated finely. You can check more in my Everycircuit page. Please visit everything. Let's dive into the calculations. Given:- Vcc=12V Ic=1mA β=100 Av=60 R(load), Rl=10kΩ Frequencyf=100 - 10kHz Formulae used:- Av=-(Rc||Rl) /r'e, (i used α=-(Rc||Rl), so by doing common algebra, Rc=(αRl) /(Rl- α) ) Vce=Vcc/2 C=1/(2πfXc) Calculations:- First we need to find Rc:- Rc=(αRl) /(Rl- α) In this we need to find α, So α=Av*r'e=60*25mV/1mA=1500Ω Now we can find Rc Rc=(αRl) /(Rl- α)=(1500*10kΩ)/(10kΩ-1500) Rc=1.76kΩ Vc=Vcc-IcRc=12V-(1mA*1.76kΩ) =10.24V Ve=Vc-Vce=Vc-Vcc/2=10.24V-6V=4.24V Ie=Ic((β+1) /β)=1mA*(100+1) /100=1.01mA Re=Ve/Ie=4.24V/1.01mA=4.19kΩ≈4.2kΩ Stiff voltage condition for VDB:- R2≤0.01*β*Re→R2≤0.01*100*4.2kΩ R2≤4.2kΩ→R2=4kΩ By voltage divider ratio: R1=V1/V2 * R2, we need to know what are V1 and V2 are, V2=Ve+Vbe=4.24V+0.8V=5.04V V1=Vcc-V2=12V-5.04V=6.96V Then, R1=V1/V2 *R2=6.96V/5.04V * 4kΩ=5.52kΩ Coupling and bypass capacitor calculations:- C=1/(2πFXc) is the common formula we need to find the Xc for each each capacitor Xc1-The reactance of the capacitor connected to the Ac source Xc2-The reactance of the capacitor connected to the load Xce-The reactance of the capacitor connected to the emitter Xc1≤0.01*(βRe||R1||R2)→Xc1≤23Ω Xc1=20Ω Xc2≤0.01*Rl→Xc2≤100Ω Xc2=90Ω Xce≤0.01*Rl→Xce≤42Ω Xce=32Ω Take the least frequency for calculations:- C1=1/(2*π*f*Xc1) =79μF≈80μF C2=1/(2*π*f*Xc2)=1.76μF≈20μF Ce=1/(2*π*f*Xce) =49.7μF≈500μF -------------------***************---------------------- That's all the calculations. Check the rms of input and output voltage Av=393mV/7.07mV=55.58, but we assumed Av=60, This is due to some minor value errors, the capacitance needed to be slightly higher and in most of the cases Av(we get) ≥Av(given or ideal) /2 If the calculations are mostly correct. I think i covered everything, you can ask any questions, I will be happy if you see my other circuitries also. I will try to do every circuitry with its calculations.
published 9 months ago
jbasanth
9 months ago
If you want to build a small signal amplifier, use this link:- https://onlinegdb.com/n0C74X6Ff
jbasanth
9 months ago
New updated code:-https://onlinegdb.com/oK2HJE2_a this code will show the value of capacitance in terms of scientific norms

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