Bridge rectifier

586

18:50:37

Given:
Ac source→Vrms=120V
Transformer ratio=5:1
Frequency=60Hz
Calculation:
Secondary Emf=Vrms*(turns ratio) ^-1=120/5
Secondary emf=V2=24V
V2(peak) =24*√2=33.9V
Let's take each diode's voltage drop=0.8v
And remember only two diodes are active in each cycle, So, 
The output peak Voltage=33.9V-2(0.8) =32.3V
The output frequency=2*F(in) =2*60Hz=120Hz
Since, My Load=1kΩ ,
Load current=Vo/1kΩ= 32.3/1kΩ=32.3mA

published 1 year ago

jbasanth

11 months ago

The rectifier With filter circuit is created in my page, go and view that also

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