If you want a current source constant to 1 percent over a load voltage range of 0 to 10V how large a voltage source must use in series with a single resistor

Art of Electronics 3rd ed. Exercise 2.9, 2.10 (The current source in this exercise is a voltage source plus resistor) 1. When Vout=0 I1=Vin/R 2, When Vout=10V I2=(Vin-Vout)/R I1/I2=100 100Vin/R=(Vin-Vout)/R 100Vin=Vin-Vout 99Vin=Vout 99*10=Vout = 990V Exercise 2.10 Let I=10mA, how much power is dissipated in the series resistor? How much gets into the load? I1=10mA, R=99K Pr=I*U=0.01*990=9.9W on the resistor Pload=I*10V=0.01*10V=0.1W on the load