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Peaking amplifier at 10KHz

@yashgumaste
10 years ago
https://everycircuit.com/circuit/4672341152890880
The circuit has a maximum output (or 'peaks') at a certain frequency.  It is said to have a peaking frequency response, hence its name 'peaking amplifier'. The main component of this circuit is the operational amplifier (such as the 741 or 351), which is configured as an inverting amplifier with a parallel LC network in the feedback circuit.  This LC network in the feedback path is the one that determines the frequency at which the output of the circuit peaks.  This frequency fp is known as its resonant or peak frequency, and is given by: fp = 1 / [2p(sqrt(LC))].  At the resonant frequency, the impedance of the parallel LC network becomes very high. If this impedance is denoted by Rr, then the gain G of the amplifier in Figure 1 at resonant frequency is given by: G = -(RF//Rr) / R1. At frequencies below or above fp, the impedance of the LC network is below Rr, which means that the gain G of the amplifier circuit is also less than [-(RF//Rr) / R1].  This is why the output of the circuit is maximum at the resonant frequency. Here fp is 10KHz L=318mH. Xl = 2πfpL = 20Kohm C=795pF Xc= 1/(2πfpC) = 20Kohm Rr=20K//20K = 10Kohm Rf= 10Kohm Rf//Rr = 5Kohm R1= 1Kohm G= 5
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