EveryCircuit - Sine Wave Booster X20

hurz

6 years ago

hmmm, for how long is this ringing a booster 😁

lior9557

6 years ago

😁😁

lior9557

6 years ago

It seems to be a good way to get a comment

cmrincon

6 years ago

Free energy! Upload a youtube video you will be famous

hurz

6 years ago

@cmrincon, you think thats what @lior9557 had in mind, "free energy"?

hurz

6 years ago

i hope so he does NOT

lior9557

6 years ago

Hmmm i didnt think of.....free energy 🤔🤔🤔

hurz

6 years ago

too late, i dont get that out of my head you had this in your intention. So why do you think its good for comments, you have them now, but why you had this idea before you posted. Just because of this higher voltage fir a short while? It does work in real, not as good as here in simulation but it does increase the voltage. Test it yourself

lior9557

6 years ago

I know its work....i burned two inductors for that.....😁

hurz

6 years ago

637H ???? You are the master

lior9557

6 years ago

No no no !!! Its 637H at 1 hz . in real it was 10k hz so the inductor value was very low

lior9557

6 years ago

L=(sqrt(R2/R1+1)*R1)/W

hurz

6 years ago

the inductance of an inductor is a constant value (it can change, but this is only under special conditions loke saturation.) 637Henry at 1Hz is for a perfect inductor still 637Henry at 10kHz. You mixed here something

hurz

6 years ago

everycircuit inductors are perfect without any losses

lior9557

6 years ago

I know its a constant value. what i wanted to say is: you pick the inductor value by the frequency. So here in the simulation i choose input of 1 hz so the value of inductor is 637H. When i tested the circuit in real life my input was 10k hz so i hade to choose 63.7 mH

hurz

6 years ago

ok, i dont see why you do that, but i can think of a case were it makes sense. So far it doesn't make sense, why not change the sim settings to the real ones, everycircuit will not run better at 1Hz

lior9557

6 years ago

I agree !..... 1 hz its only for a comfortable calculations

lior9557

6 years ago

I changed the circuit for you to 10k hz......

hurz

6 years ago

for me, wow

hurz

6 years ago

not just for me, it cancels a lot of question mark in faces of EC users, when we see 637H we normaly do not continue to be interessted in your drawing.

hurz

6 years ago

100 Ohm, i guess is coil resistance, or have you placed extra to the existing coil resistance? 100 Ohm is an irritanting nice value, thats why im asking

lior9557

6 years ago

the 100 Ohm is a current limiting resistor. I dont want 100V with a crazy current like 4 amps 😁

lior9557

6 years ago

I wanted to limit the current 50mA max. So if the input is 5V then the resistor must be 100 Ohm

hurz

6 years ago

4A?? Hmm, have you measured the real coil resistance?

lior9557

6 years ago

Hmmm no! Because the inductor impedance in this circuit is about 4k ohm. So a few ohm of the coil resistance doesnt matter. and yes without limiting.... the current can be a few amps because of the high voltage

hurz

6 years ago

5V / a-few-ohm are not 4A! hmmmm, under what conditions you get 4A? Your diagram is not helpful.

lior9557

6 years ago

Not exactly 4A...I meant high current ! If i put 1 ohm resistor instead of 100 ohm then to get a 100V at the output the capacitor impedance will be around 40 ohm...then 100V/40 ohm we get 2.5 AMp current passing through the series circuit.thats why i put the limiting resistor

hurz

6 years ago

but you know 63.7mH will have irl already some Ohm resistance. To get against 4.04kOhm Xl=Xc some ampere current and burn a coil will be difficult, especial if 10kHz does not even hit the correct resonance frequency, its more 10.1kHz, anway still far away of Ampers. 4.04kOhm needs an exact frequency alignment to cancel Xl and Xc to zero and left over is the coil ohmic resistance + capacitor ohmic resistance ESR in both components will avoid higher available currents you were talking about. I expect tens of milli ampere. Your diagram still does not show what you have done irl.

lior9557

6 years ago

Yes XL cancel XC....but they still have their impedance refer to their voltage and current. I changed the circuit in the simulation to 1 ohm resistor....get in and see the current graph

lior9557

6 years ago

When you put 1 ohm resistor the impedance become 40 ohm not 4k ohm . In this circuit the impedance calculate sqrt(R2/R1+1) multipile R1 for inductor or divide by R2 for the capacitor. Thats their impedance . Now if you want to calculate their value you divide all by 2*pi*frequency

hurz

6 years ago

Pipo, we were talking about 63.7mH why is it now 637uH, your diagram does change with every comment we exchange, why cant you bring to begin how your real circuit looks like. You make it 40 Ohm but it was 4.04kOhm again a factor down 100. You change to get what you would like to see but not what was original on your desk? Why the hack you tune again the impedance for a factor of 100. Right now we are from tens of milli in the ampere range. Where does the factor 100 suddenly comes from. the first trick with 10000 for easier calculation, ok. Strange to hide that and we must ask for, but you explained, ok ok, not so nice, be it. Now factor 100 again. Are you kidding us?

lior9557

6 years ago

Read all again You got confused

lior9557

6 years ago

I dont know what you want??? You ask questions i answer. You cant understand my answer so you keep asking.....i changed the circuit twice to make you understand....are you sure that you even know how this circuit equation work???? Or you just like to shoot questions? You even dont know how the factor of 100 is come from.....its a waste of time... you dont know shit about rlc

lior9557

6 years ago

And who the hell is "us" its not us its only you. the problem is only in your head i spend 20 comments to explain to you something that my little kid know and you cant get it.....go and learn more elctronics kid and stop weisting my time