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leed124
modified 8 years ago

Colpitts 7mhz oscillator

3
3
213
05:24:26
The 2.5k resistor in parallel with the inductor models the estimated loses due to the finite unloaded Q of the inductor. The switch is required to provide a noise kick at the start of the simulation to get the sim going correctly. Neither of these components should be added to the actual bread boarded circuit hardware. Start the sim transient analysis, then momentarily touch the switch to give the loop a noise jolt. The inductor was built by winding 17 turns of #22 AWG wire on a T37-2 powdered iron toriodal core. The osc was designed, built and tested several years ago using the schematic as shown (but without the 2.5k loss resistor and extra start up sim switch). The transient analysis takes a little time to settle to the final values, but the sim results match closely to the actual hardware measurements.
published 8 years ago
schmooster
8 years ago
Nicely modelled. There really is no other way to kick-start the sim either lol.
gpapas1
8 years ago
Hello :) I built this circuit on hardware without the 2.5k parallel resistor, without the 100Ohm resistor from emmiter to common point of the capacitors and without the 330pF cap. It works perfectly. However I don't quite get how the feedback mechanism works and how the LC tank is formed if the L is not in parallel with the caps. I've read that Colpitts is based on the principle of feedback mechanism but I don't see any signal going back to the base of the bjt. Could someone please briefly explain these to me? Thanks.
leed124
8 years ago
hi gpapas1, Glad to hear that you actually built the circuit and it worked. I'll try to answer your questions as simply as I can. 1) The ideal DC pwr supply line is an AC (virtual) ground, therefore, the 1.16uh inductor is in parallel with the 330pf cap which in turn is in parallel with the series combination of the 100pf and 820pf caps. Just pretend the top of the inductor is at ground for AC analysis only. For DC it remains at +12volts. 2) The xstr is configured as common base by virtue of the .01uf cap from base to ground. It basically is a short to ground at the osc freq. Ignoring any parasitic capacirance, the feed back mechanism is thru the division of the xstr collector AC voltage via the 100pf and 820pf capacitors at their junction. I placed the 100 ohm resistor at the junction to provide for easy open loop gain adjustment. The other end of the resister feeds into a low impedance point at the emitter. Since the xstr is common base, the signal path is from emitter to the collector with no phase shift. Think of the emitter as being driven by a current source. The collector current is approximately the emitter current. It doesn't go back to the base of the bjt (it's at ground). Hope this helps you understand what's happening. BTW, all osc must have some sort of positive feedback to function.

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