thebugger

modified 9 years ago

Voltage Doubler Rectifier Splitter Regulator

377

04:32:46

This tiny circuit is actually comprised of four blocks. The first two stages are a rectifier/doubler. That's the 2x diode and 2x capacitor bridge. It turns AC to DC and doubles it. The third stage is the splitter stage. It splitts a single rail power supply into a split rail power supply. Usually this thing divides the voltage in half but since we doubled it first, now it's gonna be the normal maximum on both rails. The last stage is i normal voltage regulator stage, which stabilises the voltage and makes it usable for ripple sensitive circuitry like preamplifiers and oscillators. 

published 9 years ago

hurz

9 years ago

We have seen this kind of "rail split" circuit already from you! And i told you this is not properly working! Only for exact symmetric low constant load on both rails!!! Forget this way if the load does alter only a little. It has really ugly effects on the second voltage. Check this http://everycircuit.com/circuit/5565309506289664

thebugger

9 years ago

Yes the load must be symetric, but the drift can be minimized to a given extend, by sacrificing some efficiency.

thebugger

9 years ago

You just need to add a constant current draw like i did with the first two transistors. The heavier the load the higher current draw must be applied. Anyway this is just exemplary

hurz

9 years ago

Yes you can see it this way, thing which are not working are an good example on how to not do.

thebugger

9 years ago

It is working as suggested, isn't it? Voltage Doublers can't handle a heavy load, same applies for the splitter. A preamp with a nominal consumption of a few mA is a perfect load for this. There won't be much of a voltage variation with a few mA current draw. If you want to use this for heavier loads that's when it becomes impractical, but for small loads like oscillators and preamplifiers it's perfect.

hurz

9 years ago

Here we have one more good example on how to not do it. Even more, you compare your circuit with one i made. But the problem is, yours was not working! Do you see it now a year later? http://everycircuit.com/circuit/6708554887069696

thebugger

9 years ago

Yes, it's working, but the applications are somewhat limited to small loads.

hurz

9 years ago

If its just for a few mA, why not use simple resistor voltage divider? Remember you promised to make it basic! Why this pseudo dramatic transistor usage? And why the useless 5W bulbs?

hurz

9 years ago

Better use the bubls as voltage divider and not loads

thebugger

9 years ago

The bulbs are just for the show. I could've used resistors, yes but it looks cooler with lamps

jason9

9 years ago

@TheBugger Please make an FM receiver with the features of the new update. And what are you making? Why is it taking so long? Another ultimate class AB (or whatever) amp?

thebugger

9 years ago

I'm currently not working on any project.

thebugger

9 years ago

Actually I'm working on a vacuum tube amplifier but EC doesn't have valves as a component. I wish it did, though

jason9

9 years ago

Please please please make an FM receiver with the new update please.

jason9

9 years ago

PLEASE!!!

thebugger

9 years ago

You can't make an FM receiver in EC. It lacks certain requirements to simulate such a circuit. With AM it's easy, while FM, not so much. For starters FM works with a ≈100Mhz carrier, while the modulating signal is only a few Khz. Such a great difference between them prevents you from simulating a viable circuit. EC also doesn't have variable diodes (varicaps) so the design will be even harder to implement. I suggest scouting the net for fm receivers. There are some very simple topologies with IC's that only need a few external components.

jason9

9 years ago

Maybe you can make the modulator signal 1MHz, and your AMAZING surly you can do it.

jason9

9 years ago

Hey, just make a VCO for the fm transmitter. Also a 555 will work as a VCO with the control pin as frequency control.

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