Super Simple 125VAC runs 3.2V LED

123

02:31:16

A very simple circuit using only one LED, one diode, one capacitor, and 5 0.25w 1Kohm resistors. Adjust the resistor values to control milliamperes flowing through the LED. A film capacitor in the 330nf range is used. LED is this example uses 0.02A. I used 125VAC because my household outlets measure 125VAC. Typical is 115-120.

published 6 years ago

PrathikP

6 years ago

Why the 2k resistor parallel to the capacitor? It is dissipating 0.8W! You cannot use 0.5W or 0.25W resistor s. And Is it intended to be a discharging resistor or what?

PrathikP

6 years ago

Infact, the way you have built the circuit, the capacitor has little to no effect

PrathikP

6 years ago

http://everycircuit.com/circuit/5484548031512576 here I have made some changes to your circuit to reduce power dissipation.

PrathikP

6 years ago

If you just want to power a 2V 30mA LED, just use a battery and stay away from mains.

fatcat2

6 years ago

What is the purpose of the 100 ohm resistor? I'm sure it's not for suppressing the inrush current.

PrathikP

6 years ago

It is exactly for inrush limitation. Without it, many many amps would flow through the capacitor and LED and kill it.

PrathikP

6 years ago

I have now changed it to 1k. 100ohms is a calculation error.

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