EveryCircuit - Current at ground zero

6 years ago

A current source is not a singular electronic device it is in fact a voltage source with circuitry to limit its current, somewhere in its current limiting circuitry there is a point where voltage can be measured.

prinzrainer

6 years ago

because voltage don't exist without impedance

selman

6 years ago

First understand the definition of current source: it is a source which provides constant current regardless of the voltage across it... Now let’s look at your circuit, You have a 10A Current Source connected to an Ammeter, Ammeters act as short circuits to measure currents precisely so it is virtually 0Ohms. So what you’re basically doing is connecting a current source to a Zero Ohm resistor which equates to 10A x 0ohm = 0Volt! So there is nothing wrong with this circuit!!! The problem is actually with you, not understanding the basics of electronics! please read and research before making stupid remarks.

kiani

6 years ago

@wetelaudio. Anything is possible at infinity. Right!?

kiani

6 years ago

@selman. Try adding more potatoes to your meat diet. Lol

selman

6 years ago

@kiani I don’t like meat, I just love’em potato’s!!!

kiani

6 years ago

In fact zero and infinity both unreachable,, thery are relative.. Means they don't exist.. We could assume any point as zero reference,, fine,, but we will never resch it., exactly.. Check FUZZY control,,, you get to the aim point if you don't aim for it excactly, but aim closely arround it, then you get closer to target,

hurz

6 years ago

@all current sources have infinite high impedance and they like it to be shorted.

westelaudio

6 years ago

Yes you can short a current source... Never said you can't but in reality a perfect short is not possible. That's exactly 0 ohms. And this is where this "0 volts 10 amps" comes from.

hurz

6 years ago

and a perfect current source also does not exist. So what s you want to say?

westelaudio

6 years ago

@hurz indeed. I'm not quite sure what your point is. What do we even disagree on?

lenzrulz

6 years ago

Welcome to my world...😂

hurz

6 years ago

@westelaudio, are you willing to talk about perfect or imperfect power sources, so far your statements are wrong if you say current source do not have internal impedances. Perfect ones have infinite impedance and imperfect "current sources" have still high impedance, high enough to not be seen as voltage source, now you should clarify why you say current source have NO impedance cuz this is just bullshit! Sorry but this is Lennys daily world to talk bullshit, while in your case @westelaudio its the first time i see something that bad wrong from you.

hurz

6 years ago

@westelaudio, check that for imperfect power sources both in a blackbox, you cant tell me whats inside as core power, a current source or a voltage source, remember both are not perfect but very close to something perfect but anyway unrealistic from voltage current and power point of view, have fun http://everycircuit.com/circuit/5700246223716352

lenzrulz

6 years ago

Werner, all he was asking for was clarification, calm down...😬

westelaudio

6 years ago

Infinite impedance theoretically, so the current is not determined by the load? Like having a 1 meg resistor in series with a 100 ohm load and the current won't change much at 200 or 300? Is that what you mean? Yes that's correct but that's theoretical. I mean the real world conditions where parts of the current source, like bondwires will be perceived as load. So even if you connect a 0 ohm cable (that doesn't exist) it won't be a perfect short

westelaudio

6 years ago

And also, a current source in the real world doesn't work as a large series resistor. Something like a current mirror, can't be desribed as resistance or impedance correctly.

westelaudio

6 years ago

But after thinking about it some more. If all of the voltage is dropped in the current source, it's very well possible to have current without voltage, because the voltage measured across the load is voltage drop. So I was wrong about that. But still, that would be @ 0 ohms which is impossible anyways.

westelaudio

6 years ago

@hurz I can't access your link right now.

Shenobey

6 years ago

V = I . R so if resistance close to 0 can be achieved, EMF would no longer be needed to sustain a constant current...

PrathikP

6 years ago

@west you say thats it's impossible to have 0V 10A. At the output, you can. Lets assume that the output of a constant current source can be shorted with an absolute 0ohm resistance. Because of the zero ohm short, you say that the current through the short cannot be defined. But the thing is there is a regulating element (like a transistor) inside the current source, which has a resistance. When the output is shorted, the entire supply voltage drops across the trannys. The tranny has some resistance and some voltage across it. Hence, current flows through it. Also, the short circuit 0ohm connection is in series with the tranny, due to which a definite amount of current flows through it. Hope this answers your question.

hurz

6 years ago

Lenny, shut the fuck up, you have no idea what we talking here, you are still hunting for your terror hobby. YOU ARE A PSYCHOPATH.

hurz

6 years ago

@westelaudio, let me know when you can follow links properly !

hurz

6 years ago

ahh, and you forgot to answer the first question i had for you. Do you want to talk about only perfect- or more complex imperfect- power sources? Thats an very importante question. The perfect ones is a quick topic, i hope, the imperfect ones seems to be a longer one. So let me know

lenzrulz

6 years ago

Can't reason with cyberbullies...😡

hurz

6 years ago

Lenny we know your bad intentions, just talk if you have something technical, which will never happen.

sean140103

6 years ago

When the resistance is 0, no power is lost. No matter what the current is because the voltage is always 0. There is no force acting it's just electrons moving and not colliding. In a simulation I think it's not even useful to consider the components that might be within a CCS because there aren't any in this simulator. The only reason that EMF is needed is if energy is being lost in the circuit (because there is resistance.) Therefore in this circuit EMF is not needed, only the force to provide the initial 10amps. I may of course be wrong but that seems to make sense to me.

kiani

6 years ago

The symbol for A current source is represented by two parallel circles,,, means what?! An open circuit,,, infinate resistsnce,,, ie. Ideal.. Why.!? for the same reason that an ideal voltage source has zero series resistance, and the symbol is just one circle... Max. Power transfer.... Now what is the problem?! Ideal is only ideal.. Something to aim for but never to reach.,.. EC, assumes ideal, so allowing the reality to reach it. As reality is a variable,, so where would you start.!? Zero is a reference,, but., 0+0=0, why nonsense,, it is 2 zeros... current source in EC, is not so ideal, check @hurz link...

kiani

6 years ago

http://everycircuit.com/circuit/6053678033928192

kiani

6 years ago

Also check this, 👆

kiani

6 years ago

@westelaudio. Your description. Is a tatal confusion..

westelaudio

6 years ago

The description is correct. You can theoretically have current with no voltage, if all the voltage is dropped somewhere else (within the current source) but in reality, you can't. Because everything has resistance...

westelaudio

6 years ago

@PrahtikP Yes, I also came to that conclusion. But it's only true in theory. Because every wire has resistance.

kiani

6 years ago

Weste... if you check the link, you see that with low value resistor,, ec current souce still sees it as 0,, there seen to be a cutoff limit fir it on EC..

westelaudio

6 years ago

"Cannot display private or deleted curcuits"

kiani

6 years ago

It works now.

hurz

6 years ago

and as iPhone user also "unlisted" does fail. My link is unlisted