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Malcolm_McGrath
modified 4 years ago

capacitor and fading led

0
9
232
03:40:45
\When the switch is closed the capacitor charges and the led lights When the switch is opened the capacitor discharges keeping the led alight for a short time fading to off. in everycircuit with timing set to s/s you can't see a fade with timing set to 10 ms/s there is a fade switch 2 allows you to see the circuit without the capacitor timing 10 ms/s 550uF ≈ 1/2 second to fade 1.1mF ≈ second to fade 2.2mF ≈ 2 seconds to fade 4.4mF ≈ 4 seconds to fade 4.4mF ≈ 8 seconds to fade Breadboard power 5v resistor 1kohm capacitor 47uf led lights brightly fades in 1/2 second everycircuit timing s/s power 5v resistor 1kohm capacitor 47uf led hardly glows << why video www.youtube.com/watch?v=4Hg7SLhetXM
published 4 years ago
wyoelk
4 years ago
One thing, the default setting for LEDs in this app is 2v and 20ma. So the current limiting resistor would be as follows; 4.82v-2v=2.82v÷20ma=141 ohms or 150ohms
wyoelk
4 years ago
This one has an inductor to show more circuit properties _ _ http://everycircuit.com/circuit/6011425823391744
Malcolm_McGrath
4 years ago
wyoelk :-) I do like the lc oscillator
Malcolm_McGrath
4 years ago
wyoelk I understand how you calc the resistance for the led R=V/I, thanks. My current issue is coming to terms with capacitors why and how/why to choose particular cap . Got some nice formulas and vids but is still greek to me.
wyoelk
4 years ago
Well it more "geek" to me cause I don't really get it either
mlira
4 years ago
Have a look at https://www.allaboutcircuits.com/textbook/direct-current/chpt-16/voltage-current-calculations/
mlira
4 years ago
If you just want to have an led light up it slowly it's easier to have the capacitor control a transistor or something else rather than powering the led directly. That way you can use much more reasonable values for longer delays.
mlira
4 years ago
Something like... https://everycircuit.com/circuit/4705992337784832
Malcolm_McGrath
4 years ago
miira :-)

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