Why current does not flow without a ground.

148

02:48:25

Plz help me guyz..

published 10 years ago

sam88100

10 years ago

No no is stupid

7omos

10 years ago

In real life, current will flow without ground; take a battery and just connect it to a light bulb and you'll see that it will work. In simulations, it has been programmed like this because it is safer to have ground especially if the circuit has any RF components or emit a considerable amount of EMI.Think of a circuit without a ground to be like an open circuit.

firagira

10 years ago

Ground is reference to 0 volt. 1V in that circuit is potential difference(called Voltage). But, different to what potential? Put GND on -ve of batt, + side is 1V. Put GND on +ve of batt, -ve side will be -1V.

floriel

10 years ago

And there's the added problem of popential notation. In order for every circuit to show you the potential on each wire you have to define one wire as 0V by connecting a ground to it.

floriel

10 years ago

Without defining a 0V potential you could only calculate the potential differences over each component. But since we usually are more interested in "How many Volts would I measure between wire A and wire C?" it is more useful to show each wires relative potential (to the defined ground) than to show potential differences for each part.

sabda

10 years ago

You must connect gnd to circuit, and you can get light lamp if you up the volt of vsource

mherper

10 years ago

The correct answer to your question is that it is a failure in the software. In power supplies the "-" outage are often not connected to a ground, the absolute potential is then not defined, it 's floating. That enables to connect power supplies in series. For the lamp in your design it doesn't matter which absolute potential the "-" outage of the power supply has. Al long as there is a potential difference (=voltage) current will flow.

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