modified 9 years ago

Circuito astable de ond asimetrica

00:26:58

Con este diseño solo se necesitó calcular el condensador como:

C=1/((1.386)(R1=R2)(f))

C=47nF , para R=1.5k y f=10Hz (ajustado a valores comerciales)

Y se obtuvo  una onda cuadrada ideal de trabajo en alto del 50%

published 9 years ago

hurz

9 years ago

More precise within the simulation seems to be C=1/(1.526×f×R) or C=0.655/(f×R)

hurz

9 years ago

http://everycircuit.com/circuit/4522706629820416

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