modified 10 years ago

Circuito n

00:09:46

Ib = Vcc - Vce/Rb + Re (1 + Beta)
Ib = 16V - 0,7V/470K
Ib = 32microA

Ic = Beta . Ib                      Vb = 0,7V    Ve = 0V
Ic = 90 . 32microA
Ic = 2,9mA

Ie = Ib + Ic               Vce = Vcc - Rc . Ic - Re .Ie 
Ie = 2,9mA              Vce = 16V - 2,7K . 2.9mA - 0
                                 Vce = 8, 17V
Vc = Vcc - Rc . Ic
Vc = 16V - 2,7K . 2,9mA
Vc = 8,17V

published 10 years ago

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