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garr890354839
modified 7 years ago

Digital Stepper

8
4
347
04:10:08
Takes in 16 bits and sends an analog voltage between 0V and 256V (not including 256V) in steps of 3.9 mV. The 7-segment displays show what the 16 bits are, and the decimal points show the what the first 4 bits are.
published 7 years ago
eekee
7 years ago
So it combines 4-bit DACs into a 16-bit DAC? Neat. :) Hmm.. Oh I see why you've got different reference voltages for the DACs _and_ different amplifications in the VCVSs: EC's limits on what the DAC references can be. Hmm again, the math seems odd. 62.5mV x 65,536 = 4096V (!) but your high DAC has a reference of "only" 128V, which itself is twice the 64V you say and it's multiplied by 2 to reach nearly 256V... so... I'm going to assume the steps are actually 3.90625mV and the peak one step short of 256V! :)
eekee
7 years ago
I'm right! ;) The first step in blue is 3.91mV, and all the subsequent steps also match my calculations.
garr890354839
7 years ago
I need to update the desc. Sorrt.
eekee
7 years ago
No problem! I had fun calculating :)

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