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DrROOO
modified 4 years ago

✔ T-Attenuator 20dB 50Ω

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00:40:47
Assumptions: source impedance: 50Ω load impedance: 50Ω attenuation: 20dB source terminal voltage = 5 ----------------------------- since the source and load impedance is 50Ω, then the input and output impedances should be also 50Ω input impedance: 50Ω output impedance: 50Ω ------------------------------ The voltage attenuation ratio K (Vin/Vout) can be calculated from attenuation value in decibels as follow: K = 10^(attenuation/20) = 10 ----------------------------- R1 = Z * ((K-1)/(K+1)) = 40.91Ω R2 = Z * (2K/(K^2-1)) = 10.10Ω
published 4 years ago

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