Setting working point (aka Q-point) of a transistor with a voltage divider. Question: How can I make the signal symmetrical to 0V and less distorted? Any insight is appreciated.
Answer:
1. Reduce input voltage from 1V to 5mV. I found that reduction from 1 V to 100 mV also worked. --- This is the most important. Transistor was saturated at 1 V input.
2. Reduce load from 500 kOhm to 10kOhm. This made the output signal symmetrical to 0 V.
3. Fix to standard Re=200 Ohm and Rc=1.2 kOhm resistor values.
This results in amplifying AC with an amplitude of 5 mV to 40 mV (8x amplification) at 1 kHz.
Thanks for everyone's help! :)
