Digital capacitance meter with 555 timer

212

02:07:43

1 sec = 1000µF

In this case the frequency is 98,7 Hz the period cycle is 1/98,7 = 1,013171*10^-2

(1,013171*10^-2)/1000 = 1,013171*10^-5

10,13171*10^-6 = 10,13 µs ~ 10µF

If you want better accuracy:
1) change the Left 1kΩ resistor to 1MΩ
2) change the 220Ω resistor to 220kΩ

DO NOT USE ELECTROLYTIC CAPACITORS!

published 7 years ago

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