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Digital capacitance meter with 555 timer

@summoner
8 years ago
https://everycircuit.com/circuit/6456102169608192
1 sec = 1000µF In this case the frequency is 98,7 Hz the period cycle is 1/98,7 = 1,013171*10^-2 (1,013171*10^-2)/1000 = 1,013171*10^-5 10,13171*10^-6 = 10,13 µs ~ 10µF If you want better accuracy: 1) change the Left 1kΩ resistor to 1MΩ 2) change the 220Ω resistor to 220kΩ DO NOT USE ELECTROLYTIC CAPACITORS!
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