modified 8 years ago

Simple LED

01:14:35

My first Simple CIRCUIT!!!

published 8 years ago

Robert_Kidd

8 years ago

Increase voltage to 3V. LED needs 2V to light. Reduce resistor to 50 Ohm so LED current is 20mA.

Robert_Kidd

8 years ago

Explanation - with a 3V supply you need to lose 1V across resistor, leaving LED with 2V. Default current for LED on EveryCircuit is 20mA (which is 0.02A). Rearranging Ohm’s law V=I x R, resistance R=V/I or 1/0.02 = 50 Ohm.

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