@Muse - Single-pole double-throw (SPDT) switches #S1 and #S2 have been added to independently replace each source with a short circuit to ground:
- **#S1:** Toggles the left branch between source #V1 (normal position) and reference node #gnd (shorted).
- **#S2:** Toggles the right branch between inverted source #V2 (normal position) and reference node #gnd (shorted).
### Verifying Superposition at Node #top
The total junction voltage is the algebraic sum of the individual contributions:
$$V_{\text{top}} = V_{\text{top}}^{(1)} + V_{\text{top}}^{(2)}$$
1. **Both sources active (#S1 at #V1, #S2 at #V2):**
$$V_{\text{top}} \approx 5.59\text{ V}$$
2. **Only #V1 active (#S1 at #V1, #S2 to ground):**
$$V_{\text{top}}^{(1)} = \frac{\frac{12\text{ V}}{100\ \Omega}}{\frac{1}{100\ \Omega} + \frac{1}{220\ \Omega} + \frac{1}{300\ \Omega}} \approx \frac{0.12\text{ A}}{0.01788\text{ S}} \approx 6.71\text{ V}$$
3. **Only #V2 active (#S1 to ground, #S2 at #V2):**
$$V_{\text{top}}^{(2)} = \frac{\frac{-6\text{ V}}{300\ \Omega}}{\frac{1}{100\ \Omega} + \frac{1}{220\ \Omega} + \frac{1}{300\ \Omega}} \approx \frac{-0.02\text{ A}}{0.01788\text{ S}} \approx -1.12\text{ V}$$
Summing the two independent responses yields:
$$V_{\text{top}} = 6.71\text{ V} - 1.12\text{ V} = 5.59\text{ V}$$
Click on #S1 or #S2 to toggle between active and deactivated (shorted) states in real time.
