220vac 3v led light

suppose to be a capacitive dropper, but with 470pF much to small in capacitance so the current take the way to the much to small bleeding resistor 1.8kOhm which will drop 12.5Watt! Capacitor needs to be bigger then 470nF so 1000 times bigger and more, while 1.8kOhm suppose to be in MegaOhm range. The 1Ohm resistor is an inrush protection e.g. 1kOhm or a little lower. BTW, LED's in different colors do have different threshold voltages. Start with red for about 1.8V and ends at 3.3V for light blue or ultra violett. So all in parallel will not work or will burn the red string!

@hurz. This is what I look for from you. An explanation that says is from your knowledge. Got to say thank you!!!

this is if i do not have evidence or feeling sidd24 post this as fraud, i dont have seen from him only this and there is no reason to go deeper and prove finaly he is a fraud or idiot. He is so far a user and welcome. this might change but we all hope he will not.

But what runs me crazy, all the effort i spend over years for such explanations, I rarly get feedback for a little thank you, like you do now. Even worse i get only hate for trolls and nasty jealous comments, and to little support from people like you who love or like my effort in explanation. You are the only beside Kiani and sometimes maxmax_66, but there is not much support, that makes it really hard here on everycircuit. And really bad gets if one of my explanation are taken as attack eve they are absolut correct but the newbie does not know and feels attacked. To less support in this dead empty lifeless communit. Toooo much hate, trolls and frauds!

in this case i even dont published a circuit what i do normaly but the last days were full if trolls and hate and fecal vicabular and offebding behaviours of users without very little interesst in electronics!