We have a 100 mV signal at the input with a frequency of 10 Hz.
-The first amplifier is non-inverting with positive feedback, amplification approximately 6 times, 600mv
-The second amplifier is mounted inverter with negative feedback, that means it
shift the output signal with 180 *, with 3 times amplification, resulting in an amplification stage of 1.8 V
AmpIification calculation:
Non inverting: A=1+(Rf/Rin) ->
A=1+(5kΩ/1kΩ)=>A=6
Inverter: A=-(Rf/Rin) ->
A=-(6kΩ/2kΩ) => A= -3
