Constant Current LED Driver circuit nyr

152

01:56:07

Calculations and analysis.
Drain Current (Id)= IR1 = Gate Voltage (V. GV)/R1.
Here R1 =  1K
I replaced the R1 with a variable resistor (VR1) to enable me to select the required current.

If I = 814uA   V = 2.31v 
 (almost at off stage)
Then R at the drain(output) = 2.31/0.000814 = 2.837K at a minimum voltage of 2.31v
When R1 = 30 Ohms, then the current is 4.35mA

r

published 2 years ago

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