Calculating The RLC

243

03:04:20

Xc = 1/2pi f c……1/2pi (60) (40x10^-6)=66.3ohms
Xl = 2pi f l ………2pi (60) (100x10^-3)= 37.7 ohms
Z= sq rt R^2 +(Xl-Xc)^2 = 41.45 ohms
Irms = V/Z……15/41.45= .3619 [360 milliamperes]
Vr = Irms x R……. .3619x30 = 10.85v
Vl = Irms x Xl……. .3619x37.7 = 13.64v
Vc =Irms x Xc…..  .3619 x66.3= 23.99v
P = I^2 x R ……. .3619^2 x 30 = 3.92 watts 
Are the calculations off or is EC off…….
Are the calculations just a means of quantifying something not properly understood to offer an approximation creating the illusion of comprehension…
Resonant frequency = 1/2 pi x SQ RT LC…… 1/2pi (SQ RT .1 x 40 x 10 ^-6) = 79.6 HZ

published 4 years ago

kiani

4 years ago

Yoir calculation gives Rms, as youve used Rms current value... EC is showing p_p values.. Rms = peak * 0.707... So peak = rms/.707 ... Chk and see if EC agrees..!

JYounge

4 years ago

. 707 - .728. When is it appropriate to use peak values vs rms values…in terms of real world application?

JYounge

4 years ago

Seems much smoother when you adjust the frequency a bit. Thanks again for your help and guidance..

kiani

4 years ago

Ehich ever yoi use is ok, ad long as you are consistant,, if you use rms, everything ought to be rms... If you use peak value the everything ought to be peak.... If you multiply peak with rms , , you get weird unit of confusion.

JYounge

4 years ago

Ok thank you..

kiani

4 years ago

You have an rms current calculated 360mA, 360mA/0.707 = 500 mA peak.. Which is close enough EC measurement...

kiani

4 years ago

Might find this useful.. It tells you how and why the impedance of inductor is 2πfL..

kiani

4 years ago

https://www.electronics-tutorials.ws/inductor/ac-inductors.html

JYounge

4 years ago

Awesome thanks again.

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